27_Ch 19 College Physics ProblemCH19 Magnetism

27_Ch 19 College Physics ProblemCH19 Magnetism - 167...

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Magnetism 167 19.61 First, observe that () ( ) ( 2 22 5.00 cm 12.0 cm 13.0 cm += ) . Thus, the triangle shown in dashed lines is a right triangle giving 1 sin α 12.0 cm 67.4 13.0 cm  == °   90.0 2 , and 2.6 β = °− = ° At point P , the field due to wire 1 is ( )( ) 7 2 41 0 T m A 3 . 0 0 A 12.0 T 25 . 0 01 0 m π 1 1 2 I B r µ ×⋅ = × ± ± ±²³´µ¶· ± ± ¸ ±¸³´µ¶· ² ¹³´´µ¶· ² and it is directed from P toward wire 2, or to the left and at 67.4° below the horizontal. The field due to wire 2 has magnitude ( )( ) 7 02 2 2 2 0 T m A 3 . 0 0 A 5.00 T 2 2 12.00 10 m I B r = × and at P is directed away from wire 1 or to the right and at 22.6° below the horizontal. Thus, BB 11 cos67.4 4.62 T x =− °=− sin67.4 11.1 T y = −° = cos22.6 4.62 T x = +
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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