27_Ch 19 College Physics ProblemCH19 Magnetism

27_Ch 19 College Physics ProblemCH19 Magnetism - 167...

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Magnetism 167 19.61 First, observe that ( ) ( ) ( 2 2 2 5.00 cm 12.0 cm 13.0 cm + = ) . Thus, the triangle shown in dashed lines is a right triangle giving 1 sin α 12.0 cm 67.4 13.0 cm = = ° 90.0 2 , and 2.6 β α = ° − = ° At point P , the field due to wire 1 is ( ) ( ) ( ) 7 2 4 10 T m A 3.00 A 12.0 T 2 5.00 10 m π 0 1 1 1 2 I B r µ µ π = = π × = × and it is directed from P toward wire 2, or to the left and at 67.4° below the horizontal. The field due to wire 2 has magnitude ( ) ( ) ( ) 7 0 2 2 2 2 4 10 T m A 3.00 A 5.00 T 2 2 12.00 10 m I B r π µ µ π π × = = = × and at P is directed away from wire 1 or to the right and at 22.6° below the horizontal. Thus, B B 1 1 cos67.4 4.62 T x µ = − ° = − 1 1 sin67.4 11.1 T
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