28_Ch 15 College Physics ProblemCH15 Electric Forces and Electric Fields

28_Ch 15 College Physics ProblemCH15 Electric Forces and Electric Fields

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28 CHAPTER 15 15.54 The charges on the spheres will be equal in magnitude and opposite in sign. From 22 e Fk qr = , this charge must be () 2 4 2 3 92 2 1.00 10 N 1.00 m 1.05 10 C 8.99 10 N m C e Fr q k × == = × ×⋅ The number of electrons transferred is 3 15 19 1.05 10 C 6.59 10 1.60 10 C q n e × = × × The total number of electrons in 100-g of silver is 25 0 g 2.62 10 = 23 electrons atoms 1 mole 47 6.02 10 10 atom mole 107.87 g N    × Thus, the fraction transferred is 15 10 25 6.59 10 2.51 10 2.62 10 n N × × × (that is, 2.51 out of every 10 billion). 15.55 4 52 cos 2.00 10 N C 6.00 m 3.00 m cos10.0 3.55 C E EA θ Φ= ° =× ⋅
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