28_Ch 19 College Physics ProblemCH19 Magnetism

# 28_Ch 19 College Physics ProblemCH19 Magnetism - 168...

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168 CHAPTER 19 (b) Using 2 0 1 2 y yvt a t + y ∆= with 0 0 y v = gives () 2 2 20 .50 m s 6.2 m s y y t a == 0.40 = 19.63 Label the wires 1, 2, and 3 as shown in Figure 1, and let BB respectively represent the magnitudes of the fields produced by the currents in those wires. Also, observe that 12 3 , , and B 45 θ in Figure 1. At point A , ( ) 0 22 I a µπ or ( ) 7 10 T m A 2.0 A 28 T 2 0.010 m 2 4 π µ ×⋅ = and ( )( ) 7 0 4 10 T m A 13 T 2 3 2 0.030 m I a 3 B ππ = These field contributions are oriented as shown in Figure 2. Observe that the horizontal components of 1 and B 2 B G G cancel while their vertical components add to 3 B G . The resultant field at point A is then ( ) 3 cos45 53 T A B B =+ ° += , or 53 T directed toward the b A = B G ottom of the page ±
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## This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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