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29_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

# 29_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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Electrical Energy and Capacitance 63 The potential difference between the two shells is therefore, 1 1 1 1 e e e r a r b b a V V V k Q k Q k Q a b b b ab = = = = = The capacitance of this device is given by ( ) e Q ab C V k b a = = (b) When b , then . Thus, in the limit as , the capacitance found above becomes a >> ( ) b a b b → ∞ 0 4 C a π = e e a k = ab k b 16.59 The energy stored in a charged capacitor is ( ) 2 1 2 V = W C . Hence, ( ) 3 -6 2 300 J 2 4.47 10 V 4.47 kV 30.0 10 F W V C = = = × = × 16.60 From ( ) Q C , the capacitance of the capacitor with air between the plates is
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