29_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

29_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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Electrical Energy and Capacitance 63 The potential difference between the two shells is therefore, 11 eee ra rb ba VV V kQ ab bb a b ==   ∆= = − − − =     The capacitance of this device is given by () e Qa b C Vk b a ∆− (b) When b , then . Thus, in the limit as , the capacitance found above becomes a >> bab −≈ b →∞ 0 4 Ca π = ee a k →= ab kb 16.59 The energy stored in a charged capacitor is 2 1 2 V =∆ WC . Hence, 3 -6 2300 J 2 4.47 10 V 4.47 kV 30.0 10 F W V C = = × = × 16.60 From ( ) QC , the capacitance of the capacitor with air between the plates is
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