Current and Resistance
97
17.67 Note
that all potential differences in this solution have a value of
120 V
V
∆
=
.
First, we shall do a symbolic solution for many parts of the problem, and then enter the
specified numeric values for the cases of interest.
From the marked specifications on the cleaner, its internal resistance (assumed constant)
is
()
2
1
1
where
535 W
i
V
R
∆
==
P
P
2
ti
c
RR R
=+
Equation (1)
If each of the two conductors in the extension cord has resistance
R
, the total resistance
in the path of the current (outside of the power source) is
Equation (2)
so the current which will exist is
c
t
IV
R
= ∆
and the power that is delivered to the cleaner
is
22
24
2
11
i
tt
VV
R
RR
R
∆∆
=
=
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.
 Fall '10
 STAFF
 Physics, Current, Resistance

Click to edit the document details