Alternating Current Circuits and Electromagnetic Waves22921.62(a) The required frequency is 81023.0010 m s1.010Hz3.0010mcfλ−×=== ××. Therefore, the resonance frequency of the circuit is 10011.010Hz2fLCπ×, giving ()( )13126.310F40010H−−=×××22100110.63 pF2210HzCfL=(b) 200Add∈∈AC, so ( )133312206.310F1.010m8.510m8.5 mm8.8510CN mCd−−−−⋅=× =∈×⋅A(c) ( ) ( )( )10120221.010Hz40010H25 CLfLππ−=××= ΩXX21.63(a) maxmaxEcB=, so 616maxmax80.2010V m6.710T3.00EBc−−×=××(b) ()maxmax0616172720.2010V m6.7
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.