29_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

29_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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Mirrors and Lenses 295 23.54 (a) The thin lens equation gives the image distance for the first lens as ( )( ) 11 1 40.0 cm 20.0 cm 40.0 cm 40.0 cm 20.0 cm pf q == = + −− The magnification by this lens is then 1 1 1 40.0 cm 1.00 40.0 cm q M p =− The real image formed by the first lens is the object for the second lens. Thus, and the thin lens equation gives 21 50.0 cm 10.0 cm pq = + ( )( ) 22 2 10.0 cm 5.00 cm 10.0 cm 10.0 cm 5.00 cm q = + The final image is 10.0 cm in back of the second lens (b) The magnification by the second lens is 2 2 2 10.0 cm 1.00 10.0 cm q M p , so the overall magnification is ( )( ) 12 1.00 MMM 1.00 1.00
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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