30_Ch 15 College Physics ProblemCH15 Electric Forces and Electric Fields

30_Ch 15 College Physics ProblemCH15 Electric Forces and Electric Fields

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30 CHAPTER 15 15.58 As shown in the sketch, the electric field at any point on the x -axis consists of two parts, one due to each of the charges in the dipole. 22 ee kq kq EE E rr +− =−= () 2 2 4 kq xa ax Ek qk q xa xa 2  +−− =  −+ +  >> Thus, if , this gives 43 4 4 e e kqa ax q xx ≈= ±± ² ± ³ ² ³ ´ ² ´ ± µ ± ² ±² ± ± 15.59 (a) Consider the free-body diagram for the ball given in the sketch. 0 sin37.0 or sin37.0 x qE FT q E T Σ=⇒ ° = = ° cos37.0 or yy F qE T mg qE qE + ° = + and Thus, cot37.0 y x mg ° = ( ) ( ) 32 5 8 1.00 10 kg 9.80 m s cot37.0 5.00 3.00 cot37.0 10 N C 1.09 10 C 10.9 nC yx mg q EE × == + ° × = ³´µ¶· ² µ ² ³ ³ ± ² ³ ± µ (b) From Σ , we found that 0 x F = sin37.0
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