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31_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

31_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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Electrical Energy and Capacitance 65 The final charge on each of the capacitors is ( ) ( )( ) 2 1 1 4.0 F 44.4 V 1.8 10 C Q C V µ µ ′ = = = × ( ) ( )( ) and 2 2 2.0 F 44.4 V 89 C Q C V µ µ ′ = = = 16.63 (a) 1 2 3 2 e e e k Q k Q k Q V V x d x x d = + + = + + ( ) ( V V ) ( ) ( ) 2 2 2 2 2 e x x d x d x x d k Q x x d + + = ( ) which simplifies to 2 2 3 2 2 2 2 2 e e k Qd k Qd x xd x x d = = V (b) When x d and 2 2 , then x d x >> ( ) 2 2 2 2 2 e k Qd x x d = V becomes 2 3 2 e k Qd x V 16.64 The energy required to melt the lead sample is ( ) (
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