31_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

31_Ch 22 College Physics ProblemCH22 Reflection and Refraction of Light

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Reflection and Refraction of Light 263 22.59 Applying Snell’s law at the first surface in the figure at the right gives the angle of incidence as ( 11 2 12 sin sin sin sin air n n n θ ) −−  ==   ( (1) Since the sum of the interior angles of a triangle equals 180°, observe that ) ( ) 2 90 90 φθ −+° 23 3 180 , which reduces to φ =− ( . Thus, equation (1) becomes ) ( ) 13 sin sin sin si nn 3 cos sin 3 n cos  =  1 − At the smallest allowed value for , 3 is equal to the critical angle at the second surface, or 3 1 sin sin air c n θθ = . Then, 2 2 33 2 sin 1 n cos 1 =− = , and () 2 in n 2 sin 1 sin cos 1 sin s cos φφ  = Note that when
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