32CHAPTER 15 Thus, 22tan10ermg=°kqor ()( )2229220.015 kg9.8 m s0.047 mtan10tan108.9910 N mCemgrqk°°==×⋅88.010Cq−=×giving or 7~10 Cq−15.62 Consider the free-body diagram of the rightmost charge given below. 0 cosor cosyFTmgTmgθΣ=⇒==and ( )=sincossintxeFFTmganmgθθ==But, 2221254sinsin2 sineeeeeeFrrLLL22=+=+=Thus, 25taninemgL=or intan5eLmgqk=5 , 0.10 kg, and 0.300 mmLIf 4=° ==then ()()24 0.300 m0q=2kg9.80 m ssin45.99 10 Nm C.1058tan 45°°or 62.010C2.0qCµ−=±±±±²²³²15.63(a) When an electron (negative charge) moves distance x∆in the direction of an electric field, the work done on it is
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.