32_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

32_Ch 16 College Physics ProblemCH16 Electrical Energy and Capacitance

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66 CHAPTER 16 16.65 The capacitance of a parallel plate capacitor is 0 A C d κ = Thus, 0 A Cd ∈= , and the given force equation may be rewritten as ( ) () 2 2 22 22 2 2 QC CCV QQ 0 F A Cd d d == = = ∈⋅ With the given data values, the force is ( )( ) 2 6 3 20 10 F 100 V 50 N 2 2.0 10 m × = × 2 2 CV F d 16.66 The electric field between the plates is directed downward with magnitude 4 -3 100 V 5.00 10 N m 2.00 10 m y V E d × Since the gravitational force experienced by the electron is negligible in comparison to the electrical force acting on it, the vertical acceleration is ( ) ( ) 19 4 15 2 31 1.60 10
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