172CHAPTER 19 19.68 (a) A charged particle moving perpendicular to a magnetic field follows a circular arc with the magnetic force supplying the centripetal acceleration. Thus, 2vevBmr=or erBvm=The time required for the electron to traverse the semicircular path it follows while in the field is then ()()()3181939.1110kg1.7910s1.6010C1.0010Tdistance traveledrmtverB meBπππ−−−−×=====×××(b) The maximum penetration of the electron into the field equals the radius of the semicircular path followed while in the field. Therefore, and 22.00 cm2.0010mr−==×()()()1923311.6010C2.0010m1.0010T9.1110kgerBvm−−−×××==×63.5110 m s−=×The kinetic energy is then ()()22316119.1110kg3.5110 m s5.6222KEmv==××=()1810J−−×or 18191 eV5.6210J35.1 eV1.6010JKE−−=×=×19.69 With currents in opposite directions, wires 1 and 2
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