32_Ch 19 College Physics ProblemCH19 Magnetism

# 32_Ch 19 College Physics ProblemCH19 Magnetism - 172...

This preview shows page 1. Sign up to view the full content.

172 CHAPTER 19 19.68 (a) A charged particle moving perpendicular to a magnetic field follows a circular arc with the magnetic force supplying the centripetal acceleration. Thus, 2 v evB m r = or erB v m = The time required for the electron to traverse the semicircular path it follows while in the field is then ( ) () ( ) 31 8 19 3 9.11 10 kg 1.79 10 s 1.60 10 C 1.00 10 T distance traveled r m t ve r B m e B π ππ −− × == = = = ×× × (b) The maximum penetration of the electron into the field equals the radius of the semicircular path followed while in the field. Therefore, and 2 2.00 cm 2.00 10 m r × ( )( )( ) 19 2 3 31 1.60 10 C 2.00 10 m 1.00 10 T 9.11 10 kg erB v m ××× × 6 3.51 10 m s The kinetic energy is then 2 23 16 11 9.11 10 kg 3.51 5.62 22 KE mv == × × = 1 8 10 J × or 18 19 1 eV 5.62 10 J 35.1 eV 1.60 10 J KE  =  ×  19.69 With currents in opposite directions, wires 1 and 2 repel each another with forces F 12 G and 21 F G as shown in the sketch at the right. For these wires to be in
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

Ask a homework question - tutors are online