Magnetism173(a) For wire 3 to be in equilibrium, we must require that 3132FF=, or ()0130232220.0cIIddmµππ=+llgiving 21II+20.0 cm=Thus, 2120.0 cm20.0 cm12.014.00 A 1.50 A1d===−−cm (to the left of wire 1) (b) If wires 1 and 2 are to be in equilibrium, wire 3 must repel wire 1 and attract wire 2 as shown above. Hence, the current in wire 3 must be directed downward . The magnitude of this current can be determined by requiring that wire 1 be in equilibrium, or that . This gives 1312FF=212.0 cm201220.0 cm=or ()3212.0 cm0.6002.40 A20.0 cm=4.00 ANote that the same result could have been obtained by requiring that wire 2 be in
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.