33_Ch 19 College Physics ProblemCH19 Magnetism

33_Ch 19 College Physics ProblemCH19 Magnetism - Magnetism...

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Magnetism 173 (a) For wire 3 to be in equilibrium, we must require that 31 32 F F = , or () 013 023 222 0 . 0 c II dd m µ ππ = + ll giving 2 1 I I  +   20.0 cm= Thus, 21 20.0 cm 20.0 cm 12.0 1 4.00 A 1.50 A 1 d == = −− cm (to the left of wire 1) (b) If wires 1 and 2 are to be in equilibrium, wire 3 must repel wire 1 and attract wire 2 as shown above. Hence, the current in wire 3 must be directed downward . The magnitude of this current can be determined by requiring that wire 1 be in equilibrium, or that . This gives 13 12 FF = 2 12.0 cm 2 012 20.0 cm = or ( ) 32 12.0 cm 0.600 2.40 A 20.0 cm = 4.00 A Note that the same result could have been obtained by requiring that wire 2 be in
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.

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