Mirrors and Lenses29923.59(a) The lens maker’s equation, ()12111nfR=−−1R, gives 15.00 cm9.00 cm11.0 cmn−−1which simplifies to 199.05.0011.09.00n=+=+.99(b) As light passes from left to right through the lens, the thin lens equation gives the image distance as ( )1118.00 cm5.00 cm13.3 cm8.00 cm5.00 cmpfq===+−−2120.0 cm6.67 cmpq=+This image formed by the lens serves as an object for the mirror with object distance . The mirror equation then gives ( )( )2226.67 cm8.00 cm10.0 c22 6.67 cm8.00 cmpRq=+3220.0 cm10.0 cm=+m This real image, formed 10.0 cm to the left of the mirror, serves as an object for the lens as light passes through it from right to left. The object distance is , and the thin lens equation gives
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.