Mirrors and Lenses
299
23.59
(a)
The lens maker’s equation,
(
)
1
2
1
1
1
n
f
R
=
−
−
1
R
, gives
(
)
1
1
1
5.00 cm
9.00 cm
11.0 cm
n
=
−
−
−
1
which simplifies to
1
99.0
1
1
5.00
11.0
9.00
n
=
+
=
+
.99
(b)
As light passes from left to right through the lens, the thin lens equation gives the
image distance as
(
)(
)
1
1
1
8.00 cm
5.00 cm
13.3 cm
8.00 cm
5.00 cm
p f
q
p
f
=
=
= +
−
−
2
1
20.0 cm
6.67 cm
p
q
=
−
= +
This image formed by the lens serves as an object for the mirror with object distance
. The mirror equation then gives
(
)(
)
(
)
2
2
2
6.67 cm
8.00 cm
10.0 c
2
2
6.67 cm
8.00 cm
p R
q
p
R
=
=
= +
−
−
3
2
20.0 cm
10.0 cm
p
q
=
−
= +
m
This real image, formed 10.0 cm to the left of the mirror, serves as an object for the
lens as light passes through it from right to left. The object distance is
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 Fall '10
 STAFF
 Physics, Light

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