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33_Ch 23 College Physics ProblemCH23 Mirrors and Lenses

# 33_Ch 23 College Physics ProblemCH23 Mirrors and Lenses -...

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Mirrors and Lenses 299 23.59 (a) The lens maker’s equation, ( ) 1 2 1 1 1 n f R = 1 R , gives ( ) 1 1 1 5.00 cm 9.00 cm 11.0 cm n = 1 which simplifies to 1 99.0 1 1 5.00 11.0 9.00 n = + = + .99 (b) As light passes from left to right through the lens, the thin lens equation gives the image distance as ( )( ) 1 1 1 8.00 cm 5.00 cm 13.3 cm 8.00 cm 5.00 cm p f q p f = = = + 2 1 20.0 cm 6.67 cm p q = = + This image formed by the lens serves as an object for the mirror with object distance . The mirror equation then gives ( )( ) ( ) 2 2 2 6.67 cm 8.00 cm 10.0 c 2 2 6.67 cm 8.00 cm p R q p R = = = + 3 2 20.0 cm 10.0 cm p q = = + m This real image, formed 10.0 cm to the left of the mirror, serves as an object for the lens as light passes through it from right to left. The object distance is
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