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138
CHAPTER 18
Apply Kirchhoff’s loop rule around loop
abcfa
to find
( ) ( )
3
6.00
6.00
0
II
−Ω
+Ω
=
or
I
3
I
=
(1)
Apply Kirchhoff’s loop rule around loop
abcda
to find
( ) ( )
2
0
Ω
=
6.00
6.00 V
10.0
+ −
or
2
0.600 A
0.600
=
−
(2)
Apply Kirchhoff’s loop rule around loop
abcea
to find
( ) ( )
1
0
Ω
=
6.00
4.50 V
5.00
+
−
or
1
0.900 A
1.20
=
−
(3)
Finally, apply Kirchhoff’s junction rule at either point
a
or point
c
to obtain
(4)
Substitute equations (1), (2), and (3) into equation (4) to obtain the current through the
ammeter. This gives
or
and
312
II I I
+=+
0.900 A
1.20
0.600
I
+=
−
+
3.80
1.50 A
I
=
A
0
−
.600
I
1.50 A 3.80
0.395 A
I
==
18.64
In the figure given below, note that all bulbs have the same resistance,
.
R
B
±
±²³´µ¶
B
±²³´µ·
±
±
±
±
±
(a) In the series situation, Case 1, the same current
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.
 Fall '10
 STAFF
 Physics, Current

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