138CHAPTER 18 Apply Kirchhoff’s loop rule around loop abcfato find ( ) ( )36.00 6.00 0II−Ω+Ω=or I3I=(1) Apply Kirchhoff’s loop rule around loop abcdato find ( ) ( )20Ω=6.00 6.00 V10.0+ −or 20.600 A0.600=−(2) Apply Kirchhoff’s loop rule around loop abceato find ( ) ( )10Ω=6.00 4.50 V5.00+−or 10.900 A1.20=−(3) Finally, apply Kirchhoff’s junction rule at either point aor point cto obtain (4) Substitute equations (1), (2), and (3) into equation (4) to obtain the current through the ammeter. This gives or and 312II I I+=+0.900 A1.200.600I+=−+3.801.50 AI=A0−.600I1.50 A 3.800.395 AI==18.64In the figure given below, note that all bulbs have the same resistance, . RB±±²³´µ¶B±²³´µ·±±±±±(a) In the series situation, Case 1, the same current
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This note was uploaded on 12/09/2011 for the course PHYS 2020 taught by Professor Staff during the Fall '10 term at FIU.