16 - LECTURE 16 ANNOUNCEMENTS 1 QUIZ 4 A 25.7 B 23.7 C 23.8...

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LECTURE 16 ANNOUNCEMENTS 1. QUIZ 4: A 25.7 B 23.7 C 23.8 WEDNESDAY’S LECTURE TODAY 1. USING KINETICS TO COMPARE ENZYMES 2. TODAY 10/1, GRADUATE SCHOOL: WHAT IS EXPECTED OF YOU, AND WHAT ARE YOUR CAREER OPTIONS AFTER YOUR DEGREE?; 2:55PM IN COMSTOCK B108 1. THE MICHAELIS-MENTEN EQUATION, V IN = (V MAX [S])/(K M + [S]) HOW TO MEASURE K M AND V MAX BY USE OF LINEWEAVER-BURK PLOT 2. ES DISSOCIATION CONSTANT K S = k -1 / k 1 3. AN ELEMENTARY RATE CONSTANT CORRESPONDS TO ONE ENERGY BARRIER TO REACH A TRANSITION STATE 2. ENZYME INHIBITION 3. PANEL DISCUSSION OF INFANT SEX DISORDERS, MON. 10/4 AT 5 PM
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USING THE LINEWEAVER-BURK PLOT DATA [S], M V, M min 0.005 0.005 0.0025 0.0033 0.00167 0.0025 -1 FIRST STEP: CALC. RECIPROCALS 1/[S], M 1/V, M min 200 200 400 300 600 400 -1 -1 1/V 200 400 -400 -200 0 200 400 600 1/[S] X X X SECOND STEP: GRAPH I/V M = 100 M -1 x MIN; V M = 0.01 M MIN -1 -1/K M = -200 M -1 ; K M = 1/(200 M -1 ) = 0.005 M
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TURNOVER NUMBER : NUMBER OF SUBSTRATE MOLECULES CONVERTED TO PRODUCT PER UNIT TIME WHEN ENZYME IS SATURATED WITH SUBSTRATE. TURNOVER NUMBER OF SOME ENZYMES CARBONIC ANHYDRASE 600,000/sec ACETYLCHOLINESTERASE 25,000/sec PENICILLINASE 2000/sec CHYMOTRYPSIN 100/sec DNA POLYMERASE I 15/sec LYSOZYME 0.5/sec V MAX = k CAT [E] TOTAL CAN BE ELEMENTARY RATE CONSTANT k 2 , OR MORE COMPLEX. IT ANSWERS THE QUESTION: HOW FAST DOES THE ENZYME WORK? e.g. CARBONIC ANHYDRASE , k CAT = 600,000 / sec CONSIDER A SINGLE CARBONIC ANHYDRASE MOLECULE: ONCE ENZYME HAS A SUBSTRATE BOUND, PRODUCT IS FORMED IN 1/ k CAT = 1.7 x 10 -6 SEC LOOK AT TURNOVER NUMBER TABLE: CARBONIC ANHYDRASE, k CAT = 600,000 / sec WOW CHYMOTRYPSIN, k CAT = 100 / sec
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16 - LECTURE 16 ANNOUNCEMENTS 1 QUIZ 4 A 25.7 B 23.7 C 23.8...

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