March 25, 2011
1.
a.
x^2 6x 16 = 0
(x + 2) (x  8 ) = 0
x + 2 = 0
x – 8 = 0
x = 8
x = 2, 8
b.
6x^2 + 3x 18 = 0
6x^3 = 18
6x^3 = 18 (6x^3)/(6)=(18)/(6)
6x^3/6=18/6
X^3= 18/6
X^3=3
X≈ 1.44
c.
2x^2 – 3x – 5 = 0
D= b^2 – 4ac
D= (3)^24 * 2* (5)
D= 9 (40)
D= 9 + 40
D = 49
2.
a.
The solution I determined by using only the graph is x = (5, 1).
X^2 + 4x – 5 = 0
I obtained my answer by locating the point for the solutions by finding the point to where
the line meets the x axis. The first point is 5 because the line meets the x axis on the 5
point which determines that one solution is 5.
The second point is 1 because the line
meets at the x axis on the 1 point.
b.
The function has a maximum and a minimum. The maximum would be 10 and the
minimum is 10. The trend line puts the max and min at the numbers listed above. I used a
ruler to determine the max and min.
c.
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 Spring '10
 hutchins
 Math, Euclidean geometry

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