2010_10B_Worksheets.pdf - What is(20 \u2212(2010 \u2212 201(2010 \u2212(201 \u2212 20(A \u22124020(B \u2212401(C 0(D 40(E 4020 2010 AMC 10 B Problem#1\u2014 2010 AMC 12 B

2010_10B_Worksheets.pdf - What is(20 u2212(2010 u2212...

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What is(20(2010201)) + (2010(20120))? (A)4020(B)401(C)0(D)40(E)4020Answer (D):Distributing the negative signs gives(20(2010201)) + (2010(20120))= 202010 + 201 + 2010201 + 20= 40.Difficulty:EasyNCTMStandard:Number and Operations Standard for Grades 9–12:judge the effects ofsuch operations as multiplication, division, and computing powers and roots on the magnitudesof quantities. 2010 AMC 10 B, Problem #1 2010 AMC 12 B, Problem #1 ( a b ) = a + b .” Solution
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Tyrone had 63 marbles and Eric had 12 marbles.Tyrone then gave some of his marbles to Eric so thatTyrone ended with twice as many marbles as Eric.How many marbles did Tyrone give to Eric? 2010 AMC 10 B, Problem #2“Set up a equation to represent the situation.” Difficulty: Easy NCTM Standard: Algebra Standard for Grades 9–12: write equivalent forms of equations, inequalities, and systems of equations and solve them with fluencymentally or with paper and pencil in simple cases and using technology in all cases.
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A book that is to be recorded onto compact disks takes 412 minutes to read aloud. Each disk can hold up to 56 minutes of reading. Assume that the smallest possible number of disks is used and that each disk contains the same length of reading. How many minutes of reading will each disk contain? (A) 51 . 5 (B) 52 . 4 (C) 53 . 8 (D) 55 . 2 (E) 56 . 0 2010 AMC 10 B, Problem #3 2010 AMC 12 B, Problem #2 “Because 412 ÷ 56 is between 7 and 8, the reading will need 8 disks.” Solution Answer (A): Because 412 ÷ 56 is between 7 and 8, the reading will need 8 disks. Therefore each disk will contain 412 ÷ 8 = 51 . 5 minutes of reading. Difficulty: Easy NCTM Standard: Algebra Standard for Grades 9–12: identify essential quantitative relationships in a situation and determine the class or classes of functions that might model the relationships.
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Suppose [ a b ] denotes the average of a and b , and { a b c } denotes the average of a , b , and c . What is {{ 0 0 1 } [0 1] 0 } ? (A) 1 4 (B) 2 9 (C) 5 18 (D) 1 3 (E) 2 3 2010 AMC 10 B, Problem #4 “Note that { 0 0 1 } = 1 3 and [0 1] = 1 2 .” Solution Answer (C): First note that { 0 0 1 } = 1 3 and [0 1] = 1 2 . Therefore {{ 0 0 1 } [0 1] 0 } = { 1 3 1 2 0 } = 1 3 + 1 2 + 0 3 = 5 18 . Difficulty: Medium-easy NCTM Standard: Number and Operations Standard for Grades 9–12: understand meanings of operations and how they relate to one another.
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RectangleABCD, pictured below, shares 50% of itsarea with squareEFGH. SquareEFGHshares 25%of its area with rectangleABCD. What isABAD?ABCDEFGH(A)2(B)4(C)6(D)8(E)162010 AMC 10 B, Problem #52010 AMC 12 B, Problem #3“Half of the area of the rectangle is in the square.”
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