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Unformatted text preview: 1 2 (4)(6) sin 60 o = 12( √ 3 2 ) = 6 √ 3 Example. Find the area of the shaded segment shown below. 1 Solution. The pieshaped sector, A s , has area equal to 70 360 times the area of the circle. Thus A s = 70 360 πr 2 = 7 36 π 8 2 = 112 9 π The area, A , of the shaded segment is A s minus the area of the triangle. Hence, A = A s1 2 (8) 2 sin 70 o = 112 9 π32 sin 70 o = 9 . 03 7.4 EXERCISES 12. In Figures 1, 7, ﬁnd the area of the triangle. Round answers to two decimal places. In Problems 35, ﬁnd the area of the triangle. Round answers to two decimal places. 3. a = 3 , b = 4 , γ = 40 o 4. a = 3 , c = 2 , β = 110 o 5. a = 5, b = 8, c = 9 2...
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 Fall '11
 Kutter
 Algebra, Pythagorean Theorem, Law Of Cosines, triangle

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