11ProbHw3sol

11ProbHw3sol - IEOR 3658 Assignment #3 Solutions...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: IEOR 3658 Assignment #3 Solutions Probability October 10, 2011 Prof. Mariana Olvera-Cravioto Page 1 of 2 Assignment #3 Solutions 1. The number of ways to deal 13 out of total 52 cards is (52 P 13). For the case of first king being the 13th card, there are (48 P 12) ways to deal the first 12 cards, and (4 P 1) for the 13th, so there are (48 P 12) × (4 P 1) ways for the case. To conclude, the probabibility is (48 P 12) × 4! (52 P 13) . 2. We can reformulate the problem. There’re 6 sections, one for each color. We want to dis- tribute 100 jelly beans into those 6 sections. If 10 jelly beans are put into ”Red” section then we have 10 red jelly beans. Now, the problem is how many combinations are possible. With 1 divider we can make 2 sections. Therefore, we only need 5 dividers to create 6 sections. Now, assign one slot for each bean and each divider. Since we have 100 jelly beans and 5 dividers we need 105 slots. The problem of how to divide 100 jelly beans is the same as how to assign 5 dividers among 105 slots. Once we assign the dividers the rest of slots are filledto assign 5 dividers among 105 slots....
View Full Document

This note was uploaded on 12/11/2011 for the course IEOR 3658 taught by Professor Olvera during the Fall '08 term at Columbia.

Page1 / 2

11ProbHw3sol - IEOR 3658 Assignment #3 Solutions...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online