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Unformatted text preview: 3 ) 6 ] 3+ onto this diagram. (Leave the metal side the same and draw the new levels for the ammine ligands on the right side. Then form the new metal complex energy levels.) Based on your new diagram, what change has occurred regarding the ligand field splitting? If [Co(OH 2 ) 6 ] 3+ is a high-spin complex, is [Co(NH 3 ) 6 ] 3+ definitely also a high-spin complex or could it be a low-spin complex? c) Do the same for the complex [CoF 6 ] 3-. (Focus only the cobalt-fluorine sigma bonds, i.e., neglect the metal-fluorine pi interactions.)...
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