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notes11a

# notes11a - Static Equilibrium In Chap 6 we studied the...

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In Chap. 6 we studied the equilibrium of point- objects (mass m) with the application of Newton’s Laws Therefore, no linear (translational) acceleration, a =0 = = 0 , 0 y x F F Static Equilibrium

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For rigid bodies (non-point-like objects), we can apply another condition which describes the lack of rotational motion If the net of all the applied torques is zero, we have no rotational (angular) acceleration, α =0 (don’t need to know moment of inertia) We can now use these three relations to solve problems for rigid bodies in equilibrium ( a =0, α =0) Example Problem The wheels, axle, and handles of a wheelbarrow weigh 60.0 N. The load chamber and its contents = 0 τ
weigh 525 N. It is well known that the wheel- barrow is much easier to use if the center of gravity of the load is placed directly over the axle. Verify this fact by calculating the vertical lifting load required to support the wheelbarrow for the two situations shown. F L L 1 L 2 L 3 F w F D F L L 2 L 3 F w F D L 1 = 0.400 m, L 2 = 0.700 m, L 3 = 1.300 m

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First, draw a FBD labeling forces and lengths from the axis of rotation L 1 L 2 F w L 3 F D F L axis N 194 m 300 . 1 m) N)(0.700 60.0 ( m) N)(0.400 525 ( 0 0 0 3 2 1 3 2 1 = + = + = = + = + + = L L W D L L W D L W D F F L L F L F F L F L F
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