review1

review1 - above its launch point has the speed of the ball...

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Review for Test #1 Responsible for: - Chapters 1, 2, 3, and 4 (except 3.6) - Notes from class - Problems worked in class - Homework assignments Test format: - 18 problems (5 points each)** - multiple-choice, some T/F, 2 bonus probs. - Time: 75 minutes Test materials: - Pencil, eraser, and non-programmable calculator - No formulae sheet or paper; all provided - Closed textbook and notes - Student ID

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Material Covered Chapter 1: Introduction - Units, significant figures, dimensions - Order-of-magnitude estimates Chapters 2 and 4: 1D and 2D Kinematics - Displacement, velocity and speed, acceleration - Equations of kinematics -> solve problems - Horizontal and free-fall (1D motion) - Projectile motion (2D) Chapter 3: Scalars and Vectors - Components of a vector, unit vectors - Vector addition/subtraction - Resultant vector magnitude and direction
Example Problem (intermediate) A ball is thrown straight upward and rises to a maximum height of 16 m above its launch point. At which height

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Unformatted text preview: above its launch point has the speed of the ball decreased to one-half of its initial value? Solution: Given: y max = 16 m Infer: v y,max = 0, y i = 0 Find: y A when v yA = v yi /2 Also, need v yi y y i, v yi y max , v y,max y A, v yA To maximum height (drop y subscript in v): v 2 max = v 2 i –2g(y max-y i ) Solve for v i v 2 i = v 2 max +2g(y max-y i ) = 2gy max To intermediate point: v 2 A = v 2 i –2g(y A-y i ) Solve for y A y A = (v 2 i – v 2 A )/(2g) = [v 2 i – (v i /2) 2 ]/(2g) = v i 2 (1-1/4)/(2g) = v i 2 (3/4)/(2g) = 3v i 2 /(8g) = 3(2gy max )/(8g) = 3y max /4 = 3(16m)/4 = 12 m Example Problem 4.43 (Hard) On a hot summer day, a young girl swings on a rope above a local swimming hole. When she lets go of the rope her initial velocity is 2.25 m/s at an angle of 35.0 o above the horizontal. If she is in flight for 0.616 s, how high above the water was she when she let go of the rope?...
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review1 - above its launch point has the speed of the ball...

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