test092p2 - ~ FIGURE 1 Ll~T ~i l l ...0 Prt>b. 7 J...

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Unformatted text preview: ~ FIGURE 1 Ll~T ~i l l ...0 Prt>b. 7 J P~ YYJ q f 'c --- F F 1I~ I~SrJ 1;X':=: ',><-+ 2.,(('= ~ - Fy (N) t3 ! _ !-1 .; F,1 i a><~ is: _~ l! A -3- -t-4 m. r:: N r~ r1 ,..!..:J-. __ -I ~ () 133_ ! --r-i ~L 1 , 3 ro I"J l 4. f2., ~e\ \ A @ A E)(15.0m/52)< 1).--- A + Fs' h I), \' _ c,.f\ .,(l I Sf hi.>' I G~C> tJ )51 n 3D - S, h 2l> -- C> _ ; - 1- D 7) Cons,dty X-J,~t~01 on} F r:::- In r::- .- 5 of the <: c /")_ ..L.ly CL/ r- - B) (1.67 m/ s2)x- - (0.333 m/ s2)y C) (1.67 m/ s2)x-A (2.333 m/ s2)yA + A A D) 1.67 m/ s2)x- + (0.333 m/ s2)y .52- r>;f--i--'-i _ "q !j --i 'i.. 7) The two fOITesindicated in Fig",e 1 act on af3.000S object. What ;~elecatiOn object? A A A) (5.00 m/ s2)x- + (1.00 m/ s2)y ~ /,67J!L ~-37J l Ii t--"t ~_L~~ls tt IrJ ,'_ F, 7 -=- ~ -:3 - 1" aJfJ. v",j -+" )., s,'" L /1/1 7 A / ::::;7 1 ~ 0' ~cy) (3.00m/ s2'N_:; 8) A 1000-kg barge is being towed by means of two horizontal cables. One cable is pulling with a force of 80.0 N in a direction 30.0° west of north. The second cable pulls in a direction 20.0° east of north. What should the magnitude of its pulling force be so that the barge will accelerate northward? A) 117 N B) 58.5 N E) 73.7 N C) 120 N D) 127N 8) 9) A policeman investigating an accident measures the skid marks left by a car. He determines that the distance between the point that the driver slammed on the brakes and the point where the car came to a stop was 28.0 m. From a reference manual he determines that the coefficient of kinetic friction between the tires and the road under the prevailing conditions was 0.300. How fast was the car going wh~er applied the brakes? (This car was not equipped with anti-lock brakes.) A) 10.7 m/ s IB) 12.8 m/ s I C) 21.4 m/ s D) 45.7 m/ s E) 32.9 m/ s 4 9) 10) A mass of 40.0 grams is attached to a vertical spring with a spring constant k = 20.0 N / m and lowered slowly until the spring stops stretching. How much does the spring stretch? A) 0.0816m , 5.~ tyJq; B) 0.200 m C) 0.00200 m (< -f'Y) ~ ~ CJ D) 0.800 m ~.0196m <-t Y">~ ~ CJ 10) £ = F; k6 6'7 -" Y!2.2:~CJ,OU(~ 2 ~ (.OHttJ(r;:tll'l/JY :» ...
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This note was uploaded on 12/10/2011 for the course PHY 1111 taught by Professor Stencil during the Fall '11 term at University of Georgia Athens.

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