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3.13.
Visualize:
The vectors ,,
A B
G
G
and
CAB
=
+
G
G
G
are shown.
Solve:
(
a)
We have
ˆˆ
52
A
ij
=
+
G
and
35
.
B
=− −
G
Thus,
=
+
G
G
G
(5
2 )
( 3
5 )
=+ +
−
−
23
.
=−
(b)
Vectors
,
A
G
,
B
G
and
C
G
are shown with their tails together.
(c)
Since
ˆˆ ˆ ˆ
,
xy
Ci jC
iC
j
=−= +
G
2,
x
C
=
and
3.
y
C
= −
Therefore, the magnitude and direction of
C
K
are
22
(2)
( 3)
3.6
C
=+
−
=
11

3
tan
tan
56 below the
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This note was uploaded on 12/10/2011 for the course PHYS 1211 taught by Professor Geller during the Fall '09 term at University of Georgia Athens.
 Fall '09
 geller

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