04_P07InstructorSolution

04_P07InstructorSolution - 4.7. Solve: Visualize: Refer to...

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4.7. Visualize: Refer to Figure EX4.7. Solve: From the figure, identify the following: 1 0 m x = 1 0 m y = 2 2000 m x = 2 1000 m y = 1 0 m/s x v = 1 200 m/s y v = 2 200 m/s x v = 2 100 m/s y v =− The components of the acceleration can be found by applying 22 21 2 vv a s = for the x and y directions. Thus () ( ) 2 200 m/s 0 m/s 10.00 m/s 2 2 2000 m 0 m xx x vv a x == = Δ− ( ) 2 100 m/s 200 m/s 15.00 m/s
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