04_P59InstructorSolution

04_P59InstructorSolution - Model: Let the ground frame be S...

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4.59. Model: Let the ground frame be S and the car frame be S. S moves relative to S with a velocity V along the x -direction. Solve: The Galilean transformation of velocity is vvV = + G G G where and vv G G are the velocities of the raindrops in frames S and S . While driving north, ( ) ˆ 25 m/s Vi = G and RR ˆˆ cos sin . j v i θ =− Thus, G GG ( ) sin 25 m/s cos vi v j Since the observer in the car finds the raindrops making an angle of 38 ° with the vertical, we have R R sin 25 m/s tan38 cos v v + = ° While driving south, () ˆ 25 m/s , G and cos sin . j v i G Thus, ( ) sin cos i v j ′=− + G Since the observer in the car finds the raindrops falling vertically straight, we have R R sin tan0 0 cos v v −+ = °= R sin 25 m/s
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This note was uploaded on 12/10/2011 for the course PHYS 1211 taught by Professor Geller during the Fall '09 term at University of Georgia Athens.

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