7.34.Model:Blocks 1 and 2 make up the system of interest and will be treated as particles. Assume a massless rope and frictionless pulley. Visualize:Solve:The blocks accelerate with the same magnitude but in opposite directions. Thus the acceleration constraint is 21,aaa== −where awill have a positive value. There are two real action/reaction pairs. The two tension forces will act as if they are action/reaction pairs because we are assuming a massless rope and a frictionless pulley. Make sure you understand why the friction forces point in the directions shown in the free-body diagrams, especially force 1f′Gexerted on block 2 by block 1. We have quite a few pieces of information to include. First, Newton’s second law for blocks 1 and 2: ()net on 111k11111xFfTnTm am aμ=−=−== −G()net on111110 NyFnm gnm g=−=⇒=()net on 2pull
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