9.20.Model:We will define our system to be archerarrow.+The force of the archer (A) on the arrow (a) is equal to the force of the arrow on the archer. These are internal forces within the system. The archer is standing on frictionless ice, and the normal force by ice on the system balances the weight force. Thus ext0F=GGon the system, and momentum is conserved. Visualize:The initial momentum ixpof the system is zero, because the archer and the arrow are at rest. The final moment
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 12/10/2011 for the course PHYS 1211 taught by Professor Geller during the Fall '09 term at UGA.