Oct28_examples

# Oct28_examples - October 28th Examples(10.20 A manufacturer...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: October 28th Examples (10.20) A manufacturer of resistors claims that 10% fail to meet the established tolerance limits. A random sample of resistance measurements for 60 such resistors reveals eight to lie outside the tolerance limits. Is there sufficient evidence to refute the manufacturer’s claim, at the 5% significance level? Find the p-value for this test. Answer: H : p = 0 . 10 ,H a : p > . 10. Let X ∼ Bin ( n,p ) . p- value = P ˆ P > 8 60 H true = P X n > 8 60 p = 0 . 10 = P ( X > 8 | p = 0 . 10) = 1- P ( X ≤ 8 | p = 0 . 10) = 1- 8 X x =0 60 x (0 . 10) x (1- . 10) 60- x = 1- . 8583644 = 0 . 1416356 Note: You can find P ( X ≤ 8) where X ∼ Bin ( n = 60 ,p = 0 . 1) in R rather easily with pbinom(q=8, size=60, prob=0.10, lower.tail=TRUE) Now compare the p- value to α to reject or not reject H . (10.20 remix) A manufacturer of resistors claims that 10% fail to meet the established tolerance limits. A random sample of resistance measurements for 150 such resistors reveals twenty to lie outside the tolerance limits. Is there sufficient evidence to refute thetwenty to lie outside the tolerance limits....
View Full Document

{[ snackBarMessage ]}

### Page1 / 2

Oct28_examples - October 28th Examples(10.20 A manufacturer...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online