Oct28_examples - October 28th Examples (10.20) A...

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Unformatted text preview: October 28th Examples (10.20) A manufacturer of resistors claims that 10% fail to meet the established tolerance limits. A random sample of resistance measurements for 60 such resistors reveals eight to lie outside the tolerance limits. Is there sufficient evidence to refute the manufacturers claim, at the 5% significance level? Find the p-value for this test. Answer: H : p = 0 . 10 ,H a : p > . 10. Let X Bin ( n,p ) . p- value = P P > 8 60 H true = P X n > 8 60 p = 0 . 10 = P ( X > 8 | p = 0 . 10) = 1- P ( X 8 | p = 0 . 10) = 1- 8 X x =0 60 x (0 . 10) x (1- . 10) 60- x = 1- . 8583644 = 0 . 1416356 Note: You can find P ( X 8) where X Bin ( n = 60 ,p = 0 . 1) in R rather easily with pbinom(q=8, size=60, prob=0.10, lower.tail=TRUE) Now compare the p- value to to reject or not reject H . (10.20 remix) A manufacturer of resistors claims that 10% fail to meet the established tolerance limits. A random sample of resistance measurements for 150 such resistors reveals twenty to lie outside the tolerance limits. Is there sufficient evidence to refute thetwenty to lie outside the tolerance limits....
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Oct28_examples - October 28th Examples (10.20) A...

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