# lec11 - L ECTURE 11 M OMENTUM C OLLISIONS Momentum(Newtons...

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L ECTURE 11: M OMENTUM OLLISIONS Momentum (Newton’s Laws revisited) 1. ~ p = m ~ v is constant (when no ~ F ) 2. Impulse ~ F Δ t = Δ ~ p 3. Conservation of momentum Δ p total = 0 Bounces Coefﬁcient of restitution Oblique angle Spin

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Momentum is Mass times Velocity Wilson
The “impulse” F Δ t equals the change in momentum m Δ v Wilson

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The Force usually changes during the Impulse Wilson
Damage revisited: Increase Δ t to reduce Force Hewitt

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Damage revisited: Increase Δ t to reduce Force Wilson
Newton’s 3rd implies Conservation of Momentum m=1 m=1 v=0 v=10 p=10 p=0 m=1 m=1 v=0 v=10 p=10 p=0 BEFORE AFTER F 12 D t= D p 1 F 21 D t= D p 2

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The Principle of Conservation of Momentum In an isolated system, the total momentum before a collision equals the total momentum after the collision.
Air track demonstration of Conservation of Momentum: Elastic Collision m=1 m=1 v=0 v=10 p=10 p=0 m=1 m=1 v=0 v=10 p=10 p=0 BEFORE AFTER p = 1 * 10 + 1 * 0 = 10 p = 1 * 0 + 1 * 10 = 10

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Air track demonstration of Conservation of Momentum: Inelastic Collision m=1 m=1 v=0 v=10 p=10 p=0 m=1 m=1 v=5 p=10 BEFORE AFTER p = 1 * 10 + 1 * 0 = 10 p =( 1+1) * 5 = 10
Air track demonstration of Conservation of Momentum: Head-on Collision m=1 m=1 m=1 m=1 v=0 p=0 BEFORE AFTER p = 1 * 10 - 1 * 10 = 0 p =( 1+1) * 0 = 0 v=10 p=10 v=-10 p=-10

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lec11 - L ECTURE 11 M OMENTUM C OLLISIONS Momentum(Newtons...

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