lec11 - L ECTURE 11: M OMENTUM & C OLLISIONS Momentum...

Info iconThis preview shows pages 1–12. Sign up to view the full content.

View Full Document Right Arrow Icon
L ECTURE 11: M OMENTUM OLLISIONS Momentum (Newton’s Laws revisited) 1. ~ p = m ~ v is constant (when no ~ F ) 2. Impulse ~ F Δ t = Δ ~ p 3. Conservation of momentum Δ p total = 0 Bounces Coefficient of restitution Oblique angle Spin
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Momentum is Mass times Velocity Wilson
Background image of page 2
The “impulse” F Δ t equals the change in momentum m Δ v Wilson
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
The Force usually changes during the Impulse Wilson
Background image of page 4
Damage revisited: Increase Δ t to reduce Force Hewitt
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Damage revisited: Increase Δ t to reduce Force Wilson
Background image of page 6
Newton’s 3rd implies Conservation of Momentum m=1 m=1 v=0 v=10 p=10 p=0 m=1 m=1 v=0 v=10 p=10 p=0 BEFORE AFTER F 12 D t= D p 1 F 21 D t= D p 2
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
The Principle of Conservation of Momentum In an isolated system, the total momentum before a collision equals the total momentum after the collision.
Background image of page 8
Air track demonstration of Conservation of Momentum: Elastic Collision m=1 m=1 v=0 v=10 p=10 p=0 m=1 m=1 v=0 v=10 p=10 p=0 BEFORE AFTER p = 1 * 10 + 1 * 0 = 10 p = 1 * 0 + 1 * 10 = 10
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Air track demonstration of Conservation of Momentum: Inelastic Collision m=1 m=1 v=0 v=10 p=10 p=0 m=1 m=1 v=5 p=10 BEFORE AFTER p = 1 * 10 + 1 * 0 = 10 p =( 1+1) * 5 = 10
Background image of page 10
Air track demonstration of Conservation of Momentum: Head-on Collision m=1 m=1 m=1 m=1 v=0 p=0 BEFORE AFTER p = 1 * 10 - 1 * 10 = 0 p =( 1+1) * 0 = 0 v=10 p=10 v=-10 p=-10
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 12
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/12/2011 for the course PHYS 17 taught by Professor Mcwilliams,r during the Fall '08 term at UC Irvine.

Page1 / 33

lec11 - L ECTURE 11: M OMENTUM & C OLLISIONS Momentum...

This preview shows document pages 1 - 12. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online