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Post-lab 10 Ksp-solutions

Post-lab 10 Ksp-solutions - choudhury(fac489 Post-lab 10...

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choudhury (fac489) – Post-lab 10 Ksp – lyon – (51155) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points 0.2 M Ca(OH) 2 in aqueous solution gives 1. 0.2 M Ca 2+ and 0.4 M OH . correct 2. 0.1 M Ca 2+ and 0.2 M OH . 3. 0.2 M Ca 2+ and 0.1 M OH . 4. 0.2 M Ca 2+ and 0.2 M OH . 5. 0.4 M Ca 2+ and 0.2 M OH . Explanation: [Ca(OH) 2 ] = 0 . 2 M Molarity (M) is moles solute/L solution. We can write 0.2 M Ca(OH) 2 as the ratio 0 . 2 mol Ca(OH) 2 1 L soln We know from the formula for Ca(OH) 2 that each molecule contains one calcium ion (Ca 2+ ) and two hydroxide ions (OH ). We start with the molarity of Ca(OH) 2 and use these ratios to calculate the molarity of each ion in the solution: ? M Ca 2+ = ? mol Ca 2+ L soln = 0 . 2 mol Ca(OH) 2 1 L soln × 1 mol Ca 2+ 1 mol Ca(OH) 2 = 0 . 2 M Ca 2+ ? M OH = ? mol OH L soln = 0 . 2 mol Ca(OH) 2 1 L soln × 2 mol OH 1 mol Ca(OH) 2 = 0 . 4 M OH 002 10.0points Pure water is saturated with PbCl 2 . In this saturated solution 1. 2 [Cl ] = [Pb 2+ ] . 2. [Pb 2+ ] = [Cl ] . 3. [Pb 2+ ] = 0 . 5 [Cl ] . correct 4. K sp = [Pb 2+ ] . 5. [Pb 2+ ] [Cl ] = K sp . Explanation: 003 10.0points The molar solubility is 1. the total molarity of the solution.
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