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Unformatted text preview: 2. An object is dropped from the top of the CN Tower in Toronto, 450m above the ground. The object’s height above the ground (in meters) at time t seconds is given by ( ) 2 450 4.9 h t t =. a) Over any given time interval during this experiment the average velocity of the object will be negative because height is a decreasing quantity. Calculate the average velocity of the object over each time interval. Round to three decimal places as needed, and use correct units in each answer. 3 4 t ≤ ≤ 3 3.5 t ≤ ≤ 3 3.1 t ≤ ≤ 3 3.01 t ≤ ≤ Answers: ave v = ave v = ave v = ave v = b) Use the results of part a) to guess the instantaneous velocity of the object at 3 t = seconds. Record the answer with correct units. Answer:...
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 Spring '11
 Teague
 Calculus, Derivative, vave

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