{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}


2311_2.1ClassActivitySOLUTIONS_F11 - MAC2311 ‘ 50 LUT[0...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: MAC2311 ‘ 50 LUT [0 N5 2.1 Activity: Secant Lines; Tangent Lines; Average Velocity; Instantaneous Velocity - 1. The graph of f (A) — ~;contains point P(2 %). 21) Pint point P on the graph. Then use a straight— edge to sketch the tangent line at P(2,%) . b) Suppose point Q is positioned at (yfl). Line 135 is called asecant line. Sketch line E and calculate its slope. F042,)“ “2) ... 2%?” w M secgg 3/73.; '/2'm2. Answer: 17: = we] see M c) Rounding each answer to four decimal places if necessary, find the slope of each secant line E if the x-coordinate of point Q is... x=1 x Ii.5 3621.9 x:1.99 x=1.999 . unite; to s") {(23 toawa) Maggi 9331:5433 “‘1' “WT???W “73'“:me ”$.42 mama Answers: mm? —,‘S' mm; —,‘3’533 mmg «,Qtafil mmg ~,'?.‘§\’b nzsccg‘F-lgbl d) Use the results of part (1) to guess the value of the slope of the tangent line at P(2,%) Answer: m = ”.25. ov—l- tan Ll' e) Use your guess from part d) to write an equation for the tangent line to the curve at P(2,%) . ymy, mmtxmxi) :25 y» 3;: z: ._ fiU‘fl) Answer: Y ‘3 ‘“ ”14X “l" l 2. An object is dropped from the top of the CN Tower in Toronto, 450m above the ground. The object’s height above the ground (in meters) at time t seconds is given by h (f) m 450 —— 4.91!“2 . a) Over any given time interval during this experiment the average velocity of the object will be negative because height is a decreasing quantity. Calculate the average velocity of the object over each time interval. Round to three decimal places as needed, and use correct units in each answer. 3<t<4 3<t<3.5 3933.1 3953.01 so: he? News}. blirillité? resin? 4 3 3.9% .3.l=~3 3.0\e$ Answers: vm = w3‘i,’fi E; em = ”$387; 'E van, 2 «~29. 891m vm, : a 23' [+5 £9... 3 s S 5 b) Use the results of part a) to guess the instantaneous velocity of the object at 2‘ = 3 seconds. Record the answer with correct units. Answer: Nate: Overs Bet-é 3.094 ' NJ Over ’3 e l; .4:- 3.00m a, Vawe '33 “2%.40qu Vavg ‘3. mQfi§rOOqu gear“; it kérv WQFFflJaa’um “2-61. QM ? N “Lake, “lends viewer”: 3 wreceeclie . As we, wrll Seem iéifllvt‘fi’ «w, ‘mstamianeone velodira all” its? me les‘ZfliJ—rmg. Tlaufil "ll/m eioJeef’i IS ‘ir’muelim j downwewci of as. asee; fig .Zfi Ltrn/ oil “lame “it”? 3 reewgg ...
View Full Document

{[ snackBarMessage ]}