qz2sp08sol - January25,2008 PHY2053Discussion...

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January 25, 2008 PHY2053 Discussion Name:                                   UFID: **1. (5 pts) In an auto race, initially two cars are moving side by side at 80.0 m/s. Then  one of the cars makes a pit stop. It slows to a stop over a distance of 320 m, spends 10.0  s in the pit and then accelerates out, reaching its initial speed 80.0 m/s after a distance  of 400 m. At this point, what is the distance between the two cars? Let the car which makes a pit stop be A and the other one be B. The distance between the   two cars is given by ΔX = Xb – Xa = Xb -(320+400) = Xb-720 m Since displacement is given by average velocity times time interval, the time intervals for   the car A to stop and reach its initial velocity are given by 40t = 320   t’ = 10 s
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This note was uploaded on 12/13/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.

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qz2sp08sol - January25,2008 PHY2053Discussion...

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