qz4sm08sol - June 13, 2008 PHY2053 Discussion Quiz 4...

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Unformatted text preview: June 13, 2008 PHY2053 Discussion Quiz 4 (Chapter 4) Name: UFID: *1. (5pts) Two telephone poles are separated by a distance of 30.0 m. A bird with a weight of 25.0 N rests at the center of the telephone line between the two poles. The wire sags 0.300 m. What is the tension in the string? To resolve the tension in components, we need the angle the telephone line makes to the horizontal. Since the horizontal distance between the bird and the telephone pole is 15 m, we have tan = 0.3/15 = tan -1 (0.3/15) = 1.15. We apply the equilibrium condition to horizontal and vertical directions, and solve the equations simultaneously: T R cos -T L cos = 0 T R = T L = T T R sin +T L sin -W = 0 2Tsin = W T = W/(2sin ) = 25/(2sin1.15) = 623 N *2. (5pts) Two blocks are suspended from the ceiling of an elevator as follows: A rope is *2....
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This note was uploaded on 12/13/2011 for the course PHY 2053 taught by Professor Buchler during the Fall '06 term at University of Florida.

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qz4sm08sol - June 13, 2008 PHY2053 Discussion Quiz 4...

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