qz7sp08sol - March 7, 2008 PHY2053 Discussion Quiz 7...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: March 7, 2008 PHY2053 Discussion Quiz 7 (Chapter 7.1 -7.6) Name: UFID: *1. (5 pts) A dentists drill starts from rest. After 3.00 s of constant angular acceleration, it turns at a rate of 2.00 10 rev/min. Determine the angle (in radians) through which the drill rotates during this period. 2.00 10 rev/min = 2.00 10 2 3.14(rad/rev) 1/60(min/sec) = 2.09 10 rad/s The total angular displacement is given by the average velocity times time interval: = av t = (2.09/2) 3 = 3.14 10 rad **2. (5 pts) A car rounds a banked curve where the radius of curvature of the road is 80 m, the banking angle is 15 and the coefficient of static friction is 0.2. Determine the minimum speed the car can have without slipping down the road. We take positive x-axis toward the center of the circle and y-axis vertically up. Applying We take positive x-axis toward the center of the circle and y-axis vertically up....
View Full Document

Page1 / 2

qz7sp08sol - March 7, 2008 PHY2053 Discussion Quiz 7...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online