qz6f08sol - October 17, 2008 PHY2054 Discussion-Fall ‘08...

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Unformatted text preview: October 17, 2008 PHY2054 Discussion-Fall ‘08 Quiz 6 (Chapter 19.1-19.6) Name: UFID: *1. (5pts) An electron enters in a magnetic field with a velocity of 5.00 × 10 6 m/s perpendicular to and into the sheet. The magnetic field has an intensity of 3.00 mT, lies in the sheet and is directed as shown. Find the direction (you can just draw an arrow) and magnitude of the magnetic force on the electron. Since the velocity is perpendicular to the sheet, it is also perpendicular to the magnetic field. Therefore, F = evBsin90˚ = 1.6×10-19 ×5×10 6 ×3×10-3 ×1= 2.4×10-15 N Since an electron has a negative charge, point your fingers in the direction opposite the velocity (out of the page) and curl your fingers to the direction of the field. Then your thumb points in the direction of the force. **2. (5pts) A wire having a mass per unit length of 0.100 kg/m is placed horizontally on a 30.0 ˚ incline, where there is a uniform vertical magnetic field. The wire carries a current of 2.00 A, and the incline, where there is a uniform vertical magnetic field....
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This note was uploaded on 12/13/2011 for the course PHY 2054 taught by Professor Avery during the Fall '08 term at University of Florida.

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qz6f08sol - October 17, 2008 PHY2054 Discussion-Fall ‘08...

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