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qz7sp09sol

# qz7sp09sol - PHY2054 Discussion-Spring 09 Quiz 7(Chapter...

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March 31, 2009 PHY2054 Discussion-Spring ‘09 Quiz 7 (Chapter 21.1-22.4) Name: UFID: *1. (2.5pts) An RCL series combination of R = 50 Ω, C = 40 μC and L = 200 mH is connected across an AC generator with ΔV rms = 120 V and f = 60.0 Hz. Calculate the rms voltage across the capacitor. The inductive reactance and the capacitive reactance are X L = 2πfL = 2π×60×0.2 = 75.4 Ω X C = 1//(2πfC) = 1//(2π×60×40×10 -6 ) = 66.3 Ω The impedance of the combination is Z = √[R 2 +(X L -X C ) 2 ] = √[50 2 +(75.4-66.3) 2 ] = 50.8 Ω The rms current in the circuit is the same as that in the capacitor. Thus we have I C,rms = I rms = ΔV rms /Z = 120/50.8 = 2.36 A The voltage across capacitor is given by ΔV C,rms = I C,rms X C = 2.36×66.3 = 156 V ***2. (2.5pts) An ideal transformer has a 240-turn primary coil and 80-turn secondary coil. The primary coil is connected across an AC source with an rms voltage of 120 V and an internal resistance of 20.0 Ω. What is the average power consumed in the secondary coil if it is connected across a 40-Ω resistor?

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qz7sp09sol - PHY2054 Discussion-Spring 09 Quiz 7(Chapter...

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