qz7sp09sol - March 31, 2009 PHY2054 Discussion-Spring 09...

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Unformatted text preview: March 31, 2009 PHY2054 Discussion-Spring 09 Quiz 7 (Chapter 21.1-22.4) Name: UFID: *1. (2.5pts) An RCL series combination of R = 50 , C = 40 C and L = 200 mH is connected across an AC generator with V rms = 120 V and f = 60.0 Hz. Calculate the rms voltage across the capacitor. The inductive reactance and the capacitive reactance are X L = 2fL = 2600.2 = 75.4 X C = 1//(2fC) = 1//(2604010-6 ) = 66.3 The impedance of the combination is Z = [R 2 +(X L-X C ) 2 ] = [50 2 +(75.4-66.3) 2 ] = 50.8 The rms current in the circuit is the same as that in the capacitor. Thus we have I C,rms = I rms = V rms /Z = 120/50.8 = 2.36 A The voltage across capacitor is given by V C,rms = I C,rms X C = 2.3666.3 = 156 V ***2. (2.5pts) An ideal transformer has a 240-turn primary coil and 80-turn secondary coil. The primary coil is connected across an AC source with an rms voltage of 120 V and an internal resistance of 20.0 . What is the average power consumed in the secondary coil if it is connected resistance of 20....
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This note was uploaded on 12/13/2011 for the course PHY 2054 taught by Professor Avery during the Fall '08 term at University of Florida.

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qz7sp09sol - March 31, 2009 PHY2054 Discussion-Spring 09...

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