Exam I 2004 Solutions - CHE 339/BME339/BIO335 In-Class Exam...

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Unformatted text preview: CHE 339/BME339/BIO335 In-Class Exam #1 Tuesday, October 5, 2004 Your name Part 1: Short Questions 1. (10) A. You wish to determine the umax, KS and Yx/S of the newly discovered organism Shigella austz‘ni. For this you run continuous culture experiments in which a nutrient solution with a known concentration of the limiting substrate, Sin is fed into the tank. You change the dilution rate and measure the concentration of cells and substrate, (X and S respectively) in the outflow. Explain how you can use that data to calculate umax, KS and Yx/S for the cells you are using. (5) B. How would you obtain these parameters from shake flask experiments (i.e. from batch culture data)? A V I kt 1 k e I’ '- ’, . g . h . I "I N 5 PMUAJ €04.) &/ ’— _: 2, ,.~ +, w m AWN“? “- in S “’l‘“ i ‘3 ' M MW: “7 :3 Mae 1 4 WM J an” lay + r \ r ‘ F For L l~\L~M-D}’(‘1~'i‘ \N \Afl" 5’36.“ LA- GLL'A : KUL J/ \ \ V ‘— ,L«- l "L, .n L; / a . '3‘ l ’ 5") i6 : ‘k/S */0‘ \V 71/35, 6 \/5- g 0~~i'r» T)"" =“ U77 3 Annoy) 3 ./MI“¢“~’» ‘ "‘“N g l L! ‘,/ ~ M r. , 47” IV] ’ /K5 if “it-t. S 4/1411 [.5 '_;//bx_miuf CvK 74 ‘A ‘J ” S \ \ -24 r i f1 I \:\J(‘ 1\ a k1“ ""54 \A} S ' m L x v5. 5% 732 a... a a t I in ‘ \ e l‘ l 1 , ,1 ‘ \’ a \V pm r» u ‘ a— t , ~z Cox " UN ‘J 0 ~ . \ L l. in» r’ a J \er Ki \V'i' “fireflx \ x M 51F) L t .. , .31» ” ,I/i' '2‘ 6,,“ k) bogs g, Luv ‘ A ’ \ x __> AHNL L3 - ‘ AAA/ch a I.) ,J'xwxr—jj / V . a)“, [t ,» 7‘4 V S ) g . 10'“ From l)“ "A" in ’J V “15% (a i / . lets!" ‘ \ «a " W ‘2 in"; I “PL [J ' Ii‘.-4'~~\‘~?5 ' "flpk. \{ ~ Int-“if Ck—Z’f' ‘ f 5 s %<,; a «‘i.’ 5‘) .. , . r r ' ,_\ \\ 4': r $\ ‘ } L; lflu ’Y‘NL. Lit/L4. {7B)r‘\\“) a L u M ref 3 / fl {DA X #0 ') V flu ( 7 (7' / ’ ‘ z : t. flat, I! We on ‘- w» \/ M5. r. 2. (4) Show in a diagram of X versus D how the concentration of biomass changes as a function of dilution rate in a chemostat where the cells can adhere onto the walls instead of displaying ideal chemostat behavror. 1:7 (LAM .——//’ fffff u_\\\ .\ I \ 61 (“VJ/1A Fri T/‘D‘ Jr ‘ ‘/ \r.) (ii/in)” “In a» :\ or. at w- m%m,fiw*¢ If, . fl 0 r\ 0 D C r r clj'x (,erCL 3. (4) What is the Crabtree effect and why does it arise?‘ . . g i Lfo.\Qr3—rt_Q/ —l_ ‘vLC—Cla‘ \ S «3%. &)‘K Cu. no (’7 (’k 0 ’7); mom it" 1“.) f‘. n = ‘ . . , 3m” ‘l’LL, fi/Q-VJ'XR . 3; \f' 0 LL ex; \3 L-C CW.( 7 it‘ll; (Jum- rw 9”” “r {NP L U" ‘ ' « . \L - ll . . .— I J» ‘ .». - « 1‘." "'2 5' ,n'} t”"~ ‘b-‘u KM LAJ5 mulch MM ) a-v w a may (z. Hm I J‘ -- ‘ - ’ 6,) » ‘ s »’ ‘ . ’ _ . , ~41“ C [KW ,i‘. 01}: p5\r~"\f ()1; C» 'n’\\\‘ii17[,' 5:3 3‘ L .5) /" D {,3 )9 I the»! 1m q ’\ IP—xar’ C, ' 1.3”) ‘: \ » K , ‘ V A,‘ 3 —~ _ :' ‘ [j 0‘ Jr f ) Q 0 m bx L If» 3 {/n C Qi‘ix ~17 LL45 S N ix“: \u‘ \v7 ery'\ c; 'f r'olqt L 0:1/ ,r’ (VL/ (1 “(Via (same 91 ’MOCL\ALBT\‘QA —..t...‘) . 5 V V v ‘ Crikav\u\ ix k1 {5'1 3' /.l:":‘ Li (:Jvl : 4. (4) Explain graphically (preferably, but not necessarily by referring to the relevant equations) why sterilization at high temperatures results in lower nutrient destruction relative to sterilization at lower temperatures. Make sure that your explanation is complete. A 5 +H law‘pgngtmg {m (1;;st ) mun g A i: E- jay 1m c} L o. rain-.v IL‘K‘VJA : 5?)“ L I PU— Lkrcun FAA” / K] ‘3‘ making; Ma FL P L's. “In - '. ' fl\ K, E \ 1/ Mr { ‘lv‘f CLLSVV‘C'A‘“) " (MICXL? Cor m K‘LUA—aifl’un mm h 7%“— \ A g. l A {5" ' Lt él—AJ aiLifiUU'LC w n L “*3”? - -_ \‘ _ _ ' ~ r n LL» I i W pd r,— Ll‘juth _. AVA?!" “JET CON.“ AN If“) Ail-b élvcfiw e— DL’fl’: “(Mn .Uafi E 3 C3”? Lwa Evy _ 34,5?» JC‘J" I if ( (lurk/JP fwiv r, W=’ «\1HL o LLl‘s-bJ'Afii"? SPOT L oKJJ‘l‘FWijs l Lil”th ~ 6)“ Wm (J‘an 1/‘K :LMA chxlwvr‘té/ w» A c3 Gem/difm/“A P r L ALJ-l'rwf/‘lnun WTOCL +Kn. I LAAV LIVCJT'LAJ n 5. (6) How does the dissolved oxygen concentration at steady state depend on cell mass and growth rate? Describe three approaches that are used to prevent oxygen limitations in high cell density fermentations. AR” sir—Lng 'f Fag, Oil; Coéjwfiplmg,‘ : .F'oc‘fi. crl‘: 0L 41‘chth ii QQL;£:Y:— Qoha (A4 \i ilOL ‘ X ac ‘ . 4: X. :‘A— stag. cot / 00.3 ms to. = not - ALL-w . V 'L y (l \ii/O‘e kl.“ ' ¥/DL :) \‘LL. LV 1 1m art mg, {WR‘LG‘ 0) Far-\TC. low vi: f;\" +0 V” (Fm! JV l2.” USKK 6‘"! Elf dc “kWh” wkmdq ‘ fl ch'LJ—U 4k!» _\ m)fo retain RFC (N 0L girflflsh/ ( [gnaw 331‘" O“ SmALLr lonkLbkLJ) a =..«l.~'z“=. ,1 l ,«ipV—Lau. UK (WV-’1’ qr S ["(ci/ijf/L 44)) C, 7’0 “we L— . TV. lx‘cxl‘nldr l "(I \=m\ri.‘~é-¥' iio-L ‘. til-5 (KL/15M» [Oftfjwr-L, O z U20» uf‘) Uni-k, c. rr(...'u3m’ vi; \ . . . . 4 ‘r \lex.“ pr.ae’+v 6. (3) What is a bubble or air-lift bioreactor? C 0‘ A gntbu or aor- 41;?!» rad-=3” I l . "wl-I‘Z'L‘i‘ 0” 030‘s YPVV'S‘Z‘CJ flier 0~fili2~flnnn , \ s ‘ a (+sz KLUL v20 Mel—oft):an 0-CJ“'-.*m (~\ In bulk «lies/10‘»; / ‘l’lxs— rwr X FL . - 1 x l‘ . 5 ’ \ ., HMO-r 1" QuJ g (2 hr C34. "r 'A'n 1:1; "roe-Ii on“. Err-'- "E‘mth r‘ r; L c *M ’ L .f‘ Lo» 14. 3 M V‘Y’ ,0 E v. 9- w\~;\ ck \ f‘\ éWU/S MN I I“ 0; z A “Hug f‘L—a-ero/ . 7. (4) Why is foaming an issue in fermentations and how is it detected and how it can be minimized? «no SL/(KO-Cic‘ } LOW“ Wt"? ill-WI / ldcrl'kJ‘fW/l lorv‘jfwri (Kaila 0“ch 6J1,ch fiJI-nj 5 0‘.) (AUJ . F0 9‘ h“ “\J 0 Pf; U“ (LL 3 5‘ p 0\¥% VJ 00:) r’ LE rx 4,—0er ('Ah‘ri 0:} Cb\\5 7L0 ~—Ln l—K/ 'l/\——L. r-Le kibOr ‘ I - 47—0 (NPR "\rfi Coca L—L civic-geld ’l," NVLKvKLOIQFW‘ 6' “.5 flak pF-k—ISW’LJ Cx/xcl‘n \{k Sud—bob? l\xuo lat/1m} (firs, \* m N —\—z_«‘\(—/ I” D A r- ' 9.9 54» L D/‘ugxfan LL {1- u, ML, (He/x} L-rx..\ £173 A Er-Lkl-Lflur o f . ».f\ , , n o‘ M 6~ ollifi‘un firm (4:, — a {fl—Wt.— leQJ-{x‘ 1 L\ a. (filly-“Ari r 8. (3) A) Why do mammalian cells require an atmosphere rich in C02? -. ~~ g ‘ u l ' I fix kg' ' ( 7 J» In. (._.\__LJ:£ [M +2: or K QQ luv lot“, Mtg/urn]. c. ‘ ' 61“— ioq‘) O 0 lg I ~ 5’ u '- 1 ' i ‘ ACIL ' I Sam r , . ~'»t,- 0 Chm/Ci C rvl Lam-H41" (SMLJ L’Q‘Jf (Mm; rn ml CLAL! § In U. W R‘ a a 0 0mm v {.5 r w S (3) B) What is apoptosis and what are transformed cells? 11" )i: "UL/\fii‘x’i‘" abum'fir“ fifinf‘b Mortars wé- wk l a . i T. k» a .5 r. . , a r . . —. ’5‘. », 2m . i‘ H, (I. ( 13 3. f; n, K «1, 1‘75, Fr .3 l—ng ,m “rt—k» (Jvl l i Arr-i Si“; 4,. L. s"). 2"- : t -3-‘:. Ge“ 9.. C (2*... V (m ~ ~— ‘ - l . . \A l - . ‘ _‘__\ C, \_‘= r hazy—5r (/Q‘A c,.o/\AI‘\'F\J‘WL 4‘0 C‘M‘J‘ CU“ TV o~x~§aLa (Wad, (/kll- 5 Gil/L I r“ m“ f \' “Vi; an)“ .~,.-,_""‘L.J A,‘ A a w: <\"\r\sw\’ M if Lynn Ll)./ O l‘/\ U, {w ,1 C,“ x 13-4.. C... “ op HS: 3‘ 9. (4) Briefly describes the two key processes that occur when cells are starved for nutrients for prolonged periods of time. How does the cell concentration change with time under these conditions? . . ~ , L Tint—$4 ‘ )4 f‘ ~ ', \,_A ’ \, __ ‘ (L J“ Jr. a \v“ Xian} ML JV «id—4,11 l. C. L v pm Lpi n.) Wt» ‘ ‘T—ON L\ s v’a-A’L {WU \ \J 1* Ur“ éJ/ 5. 3 C Jt- ; Lon C '\ ‘- l “filly-J.“ .. ‘ ~ I 1 El 7 \ ' '.l ,éJ‘x whitest 5 / ,n‘,,\:{__\lf,wq ! AM 0““: LL‘ ! in kwgoi‘xl ofw‘i Sufi/043,1, a)”. {)Qure Sci 0 f3 Nag . f\ &. xw ? \ t . ~ .‘ . L L. ‘ A ~ . as 0AA a” WWW ’ ' v . t - .3» ‘M L. “ Rum rh—u akin/an o L WW “JA- AMA“ I 5,“ NVL [fish/’3 Q {vsé-n/x‘rJ-m f (firs. (fat-.5 15"»: C\\\ C'VJJ L" ”‘ \ ~”* 1 ‘ A V‘) ‘ \ .. ‘L M v I r . ., t ~ 7 4» ’1 4" it i/w E'S’Urflx 43.". (JV\\ \«-in3 5‘ {war/W NED/L” t“"-’15'i"v“'\ 'i‘3 h"*‘ 4" “M um W‘ V 1 H L L. L {I r: S qVJ/n/L 5 5674 r1 3 ‘ ‘ \ I ‘i .V r L" H T‘~>\ ‘o'xo m in: 5 MKwaMJ 01 LL“: sly LEM L; «A, %L\V3Qm0~ks 5' For our/L, M~r~---.:*~~..r\ 0' \J (7 ' W. CK {up Q‘U‘ir'~"'\1‘1"~°~hi.fl.f,. ch t o r' Jar m 3:" {J 4 10. Define in one sentence (2 pomts each, 10 points total) . > x 1 m ! 5.x,» 1. e ’n’xo‘xw if 0‘15“ A) True Yield coefficient: ” (/5; DAL) its. am oi (of 17¢" 5 0"“; U“ V’Et’i ' - . . . ‘i r ’ , x 3.0 a grandam) . \ 2‘) Lot BF“ Fall < chain; at" V\ (in 54* M“ r“ “1“ U" 4 r S L9“ J 'Vkpm I B) Ball mill \ MA’k (\21.\ D 0' 0E 5‘ ) n6} E in. (1 1’ f: v. 1...:7 y-x~\J,_,{_,,£~-~fi~ (“EL—tail ELL; 0h 5/ L,L/\,\5 Cf VJ 1"”‘fi {1 C) Respiratory quotient p “g Cram CAM I 1' AR RM team : [n \ s; (_/x 3“ f a v ~ A“ {aura/L, Q Q —; m 0L1. S ‘J “' 3 L0 mix). ‘0, A r-m :. I\ f“ 3 LL; 01" ‘Iw’ 1» CL?)’\£U-"r~f._ C: D) Secondary metabolite I < {a a, , it \ fix with. (J N if? Law (l l ,\ \‘p 3;, > l ."\)f mm)“ D Okra“ Awe”, C/k 1‘ K V w a {)7 Proocmix.‘ bah”! ‘ r r . \ ‘ I),1 /x'__.i [J A“; ACCILJIWK} I, , ( , {a}, m’ x Imp) $41.11*:ch 27 f) a. L ‘0 r 0 (how. L"? w! J" r“ O 5~J~.,~ em ULD/ (“Lift (1‘ .10qu 4:? CH” jtraf \5: U:~\\ . E) Critical dissolved oxygen concentration x f . v "I . ' L» -\J- x L 1. . A rr‘x’v’ L “w pa. i m 1 nr‘\ 0. N\ O 7—.- C Q r\ {Qty-31f u~.‘\,‘x \3 A u_ ar ‘1 s 6, «m x C. 0 ~- 0 i (—— U l _ _ I, 1 " l \ 7m? Llrvrt'jn (\ J ,~'~. . C 0n LEAXFLK- man Wdfiikiwtg (so one) o i c zl- \-J»l-"5‘L 0" “ ' ~ I ‘l ‘ v _ 4 j“ l V: 5' H \k bn+ I M \XA \ [\h.\). rm V," L_ \JJ ‘vx‘ I; (A {3, “V :5 f‘ '3 ‘ J ,3 Ask 7:, (:3 AA fwd/75 . PROBLEMS 1. Problem 1 (15 points) A jar containing 10 liters of media with 105 spores/l is to be sterilized at 121 0C for 20 minutes. However, the sterilizer malfunctions and the temperature reaches only 119 OC instead of the desired temperature of 121 0C. What is the probability that the medium Will be sterile (i.e. the value of NI)? At 121 0C, Kg: 1.0 min‘1 and Ed: 90 kcal/mol. R=1.987 kcal/mol K ' ~Ei a \ééfi/ kge’ W1 ’9 A: \CA/ L-\;c\i(LT A; )‘OMtnr‘\ / C / SLCLl \C‘m hth kc _\ .. A; [./7, mm A wfllmr .\ : \.\Lm:" Q2569 a ’K I +5 \<o\ H“! L“— .C’tqg MFA 5/? 3 U f a“; i 5—,.0r—k5 ND , [o Sfl/f, 1 /0L P L. X“ : ‘ng % No x V Sc r3" Min) \n 10/ z 0 ’" :er Q -° ' [0 3 <0 we ~=v / ~ LN” \n “— l N‘; , KL fly '- :34 . Z w ’ 5’0" M (a {M —— 0.002 cf ‘7“ x: \ \\ 5D Pffllfif'it’i‘ O \ D Z ‘900 or Problem 2 (25 points) In a chemostat with cell recycle, the feed flow rate and culture volumes are F = 100 ml/h and V: 1000 ml, respectively. The system is operated under glucose limitation, and the yield coefficient, Y)?” is 0.5 gdw cells/g substrate. Glucose concentration in S thefeed is So = 10 g glucose/l. The kinetic constants of the organisms are ,uM = 0.2 h}, Ks = 1 g glucose/l. The value of C is 1.5, and the recycle ratio is a = 0.7 . The system is at a steady state and the cells obey Monod kinetics. A. Derive an expression for u as a function of D and then find the substrate concentration in the recycle stream (S). B. Find the cell (biomass) concentration in the recycle stream. C. Find the cell concentration in the centrifuge effluent (X2). MLA‘VV‘I‘ I;\\r(o Maj} [DOAOUJ‘UV “A UA\S‘ ‘ AKA, Spin Fioir <\+'J¢3\:XI+\]MI\L‘% (lzv div (A. 31,1 ~, Cw, (M: Q 3: \ififnki‘, LLLCX ‘. ,0 3, O V , A 1 0 UL F 04. (pram xxx, r VMN;., ,/()\M’f\"'>— "S < C v \\ 1:: M“ “‘3? 2' E 1 4'0)‘ 1' C\3 U , 5/). 5‘ (000%: ,x. :1 0. 90:5 k/ ’5 9" Edgy“: “ W7 o M. 9 all t 3 (2%,: As " C3 ID“ L‘r’ } > \ m {open—L \7 . / IV 63 (AW @\ \/ ‘ \,»(SBV§)\}H5 - «[ggqu) (O—«ng (JAM), [3/ \ ‘ N /( _‘”_ '_,_W.._V.'———v ‘—»v———__.._._,._,,___,,____>___#_W__fl_¥~~> “(m (7‘ ‘5’ \‘Krr \<( :7 3 LiL» >lpr¥f Xe XV? l0 r(5 3/, X O.\\ ELF Ara» ,r I \ (2; -\ V f L\~. Cnrgybg . k, kw Cficx : \ W) (wen < .1, UV,» /, V / \ f \/L‘ (\,9\\{\(~va(“1( / 1 \\ / fi'\\ } l/ — /1 \l’TK'Ttsr'lLi -kQ ,“J K ’ \I’vz- “i ‘ i L '1 f»; . ...
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Exam I 2004 Solutions - CHE 339/BME339/BIO335 In-Class Exam...

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