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10sE2FirstFewProblemsSoln

10sE2FirstFewProblemsSoln - Prof Girardi Math 142 Typical...

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Unformatted text preview: Prof. Girardi Math 142 Typical First Few Problems on Sequences & Series Exam If you do not make at least a 50% on this exam’s first few problems, then your total exam score will be only as many points was you managed to get on the first few problems. Here are some typical first few problems. 00 1' Fill—in—the blanks / boxes. All series 2 are understood to be 2. =1 Hint: You should NOT write the words absolute no: conditional on Problem 1! 1a. Sequences (Afterall, this is needed for Geometric Series!) Let —oo < r < oo. (Fill—in—the blanks with exists or does not exist, zle. DNE) ' If M < 1, then Elfin—>00 M w— ' If [Tl > 1, then limn_,oo Tn _Dfl_l_3___________ ' Ifr=1’thenlimn—>007'n exists (= 1. o If r = -1, then limn_>00 r” DNE ( 05c.) 1b. Geometric Series where —oo < r < 00. The series 2 r” o converges if and only if |r| < I o diverges if and only if |r| Z I la. p—series where 0 < p < 00. The series 2 n—lp o converges if and only if p > I o diverges if and only if p 5 \ 1d. Integral Test for a positive—termed series 2 an where an 2 0. Let f: [1, 00) —> R be so that oan=f( h. )foreachnEN o f is a EOSH'NC function . f is a oon+in mo LL$ function . fisa dearcasm or o incrcasu‘n function. Then 2 an converges if and only if 5 :0 10 (X) 4% converges. 1e. Comparison Test for a positive—termed Series Z on where an 2 0. . HO 3 an 3 bn for all n e Nand gm 00 n Vargas ,then 2a,, con Verges . oIfOSbnSanforallnENanden chfljc‘} ,thenZan Cit/M365 . 1f. Limit Comparison Test for a positive-termed series 2 an where an 2 0. Let bn > 0 and limn_>00 2—: = . If 0 < L < °O , then 2 an converges if and only if Z L”‘n mvwc’fbé. 1g. Ratio and Root Tests for a positive-termed series 2 an Where an 2 0. 1 Let p = limnnoo a"—+1 or p = limnmoo (an)? , an o If p < J- then 2 an converges. o If p > 1' then Zan diverges. o If p = 1— then the test is inconclusive. 1h. 1i. 1k. 11. 2 Alternating Series Test for an alternating series Z(—1)"an where an > 0 for each n E N. If 'an___>__an+1f0reachneN (clecrcmslnj§ o limnnoo an 2 0 then Z(—1)“an M— nth—term test for an arbitrary series 2 an. If limn_,oo an 7é 0_ or limnnoo an does not exist, then 2 an Al Ve—E 3&5 . '. By definition, for an arbitrary series 2 an, (fill in the blanks with converges or diverges). 0 2 an is absolutely convergent if and only if E |anl Com) as 0 2 an is conditionally convergent if and only if 2 an Co Q‘V egg and Z lan| fish/rag 0 2 an is divergent if and only if 2 an clN mag If a power series in :r — 330 has radius of convergence R where 0 < R < 00, then the power series is: o absolutely convergent for 'X, c R < 96 4 ’X, {a K o divergent for X 4 X9 " R GMA- 1 i' R 4 1 Consider a function y = f (ac) where f: [1, 00) —> R . Next consider the corresponding sequence {0,7,}le where an déf' f (n) o If the limit of the function y = f(:r) as so —-> 00 is L, then the limit of the correSponding sequence {an}$,°:1 as n ——> 00 is L . o If limnnoo an 2 L, is it necessarily true that lirnQHOO f (3:) = L? Circle: Yes or Fill in the 3 blank lines (with absolutely convergent, conditional convergent, or divergent) on the following FLOW CHART for class used to determine if a series 22:17 an is: absolutely convergent, conditional convergent, or divergent. Does 2 [an] converge? ‘fNO a is 12> Z n ngg moi” Since ian| Z 0, use a positive term test: integral test, CT, LCT, ratio/root test. if YES 1; if YES U Is Zen an alternat- ing series? Does 2 an satisfy the conditions of the Al— ternating Series Test? 2a,, is CmOlli’laanl% Cmgcragat 3. Circle T if the statement is TRUE. Circle F if the statement if FALSE. To be more specific: Circle T if the statement is always true and circle F if the statement is NOT always true. Scoring: 2 pts for a correct answer, 1 pt for a blank answer, 0 pts for an incorrect answer. @ F If 2 an converges, then lim,H00 an = 0. T G?) If limn—aoo an = 0, then 2 an converges. ( L3 ) an = AL) T @ If a sequence {afiffizl satisfies that lim,H00 an 2 L and f : [0, 00) —> R is a function satisfying that f (n) = an for each natural number ' then limmnoo f(:c) = L. Con/pedal.” H’X) '—' 3‘“ (THC) . ‘ @ F If a function f: [0, oo) ~—> 1R satisfies that limgc_,00 f (cc) = L and {afifiozl is a sequence satisfying that f (n) = an for each natural number n, then limnnoo an 2 L. @ F If 2 an converges and 2 bn converge, then Emu + bn) converges. I T ® If 201.7, + bn) converges, then 2 an converges and 2 bn converge. 6.2.2 (Ln-,1 ‘ ‘N 7.17 _ 7.N+1 bu 5F; Cr) F Ifr¢1andsN=Zrn,thenSN=—1:-;—foreachN>17. n=17 NOTICE, the above sum starts at n = 17, not at n = O. MORE => 4 4. Geometric Series. Let, for N 2 102, N 2n SN 2 Z 37n+1 ' n=102 4a. Do some algebra to write 3 N as 22,le c 7"” for an appropriate constant c and ratio 7". 4b. Using the method from class (rather than some formula), find an expression for s N in closed form (i.e. without a summation 2 sign nor some dots .). ...
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