This preview shows pages 1–6. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Can we see any interference without a laser? Some math: the slits are two coherent sources . The distances to the observation points are r 1 and r 2 . Their difference θ sin 1 2 d r r = − L y L y / ) / ( tan 1 ≈ = − θ L dy r r / 1 2 ≈ − for small angles θ , small y/L Constructive (a bright strip) θ sin 1 2 d r r = − L dy r r / 1 2 ≈ − λ θ m d = sin Destructive (a dark strip) λ θ ) 2 / 1 ( sin + = m d θ Approximation used: L d << for small L y / In the case when 1 / << L y L y / tan sin ≈ ≈ θ θ L y 1 r 2 r y ) ( y S 4 S 2 S Positions of the bright and dark fringes (maxima and minima of interference) d L y λ = Δ d L m y bright λ = d L m y dark λ ) 2 / 1 ( + = The distance between the fringes: d L y / λ = Δ θ ... 2 , 1 , ± ± = m Angular positions of the bright and dark fringes: d m / sin λ θ = d m / ) 2 / 1 ( sin λ θ + = ) ( cos 4 ) sin ( cos 4 2 2 y L d S d S S λ π λ θ π = = Does this look any familiar?...
View
Full
Document
This note was uploaded on 12/13/2011 for the course PHYS 2C PHYS 2C taught by Professor Groisman during the Spring '11 term at UCSD.
 Spring '11
 groisman

Click to edit the document details