21 Optics 6

21 Optics 6 - Can we see any interference without a laser Some math the slits are two coherent sources The distances to the observation points are

This preview shows pages 1–6. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Can we see any interference without a laser? Some math: the slits are two coherent sources . The distances to the observation points are r 1 and r 2 . Their difference θ sin 1 2 d r r = − L y L y / ) / ( tan 1 ≈ = − θ L dy r r / 1 2 ≈ − for small angles θ , small y/L Constructive (a bright strip) θ sin 1 2 d r r = − L dy r r / 1 2 ≈ − λ θ m d = sin Destructive (a dark strip) λ θ ) 2 / 1 ( sin + = m d θ Approximation used: L d << for small L y / In the case when 1 / << L y L y / tan sin ≈ ≈ θ θ L y 1 r 2 r y ) ( y S 4 S 2 S Positions of the bright and dark fringes (maxima and minima of interference) d L y λ = Δ d L m y bright λ = d L m y dark λ ) 2 / 1 ( + = The distance between the fringes: d L y / λ = Δ θ ... 2 , 1 , ± ± = m Angular positions of the bright and dark fringes: d m / sin λ θ = d m / ) 2 / 1 ( sin λ θ + = ) ( cos 4 ) sin ( cos 4 2 2 y L d S d S S λ π λ θ π = = Does this look any familiar?...
View Full Document

This note was uploaded on 12/13/2011 for the course PHYS 2C PHYS 2C taught by Professor Groisman during the Spring '11 term at UCSD.

Page1 / 10

21 Optics 6 - Can we see any interference without a laser Some math the slits are two coherent sources The distances to the observation points are

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online