hw_1 solution

# hw_1 solution - Homework#1 Solution For Sand Given m1:=...

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Homework #1 Solution 1. Given: For Sand, γ m1 116.4pcf := γ sat1 121.4pcf := K 1 0.35 := For Clay, γ m2 112.4pcf := γ sat2 117.4pcf := K 2 0.50 := γ w 62.4pcf := σ v γ w 8ft () γ sat1 10ft + γ sat2 8ft + 2.652 ksf = := u γ w 26ft 1.622 ksf = := σ ' v σ v u 1.03 ksf = := 2. σ ' v γ sat1 γ w 10ft γ sat2 γ w 8ft + 1.03 ksf = := 3 σ v γ m1 10ft γ m2 2ft + γ sat2 6ft + 2.093 ksf = := u γ w 6ft 0.374 ksf = := σ ' v σ v u 1.719 ksf = := σ ' h K 2 σ ' v 0.859 ksf = := σ h σ ' h u + 1.234 ksf = := 4. Given: γ sat 23 kN m 3 := γ w 9.81 kN m 3 := K 0.5 := (a) σ v γ sat 7m 161 kPa = := u γ w 68.67 kPa = := σ ' v σ v u 92.33 kPa = := σ ' h K σ ' v 46.165 kPa = := σ 1 σ ' v 92.33 kPa = := σ 3 σ ' h 46.165 kPa = := (b) τ max σ 1 σ 3 2 23.082 kPa = :=

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5. Given: R 6ft := q 5000 lbf ft 2 := Using P & B Chart: aR6 f t = := r0 := at z 1.5ft := z a 0.25 = r a 0 = I 0.99 := Δσ v qI 4.95 ksf = := at z 3ft := z a 0.5 = r a 0 = I 0.9 := Δσ v 4.5 ksf = := at z 6ft := z a 1 = r a 0 = I 0.65 := Δσ v 3.25 ksf = := at z 9ft := z a 1.5 = r a 0 = I 0.42 := Δσ v 2.1 ksf = := at z 12ft := z a 2 = r a 0 = I 0.28 := Δσ v 1.4 ksf = := Using Boussinesq formula: B2 R 12 ft
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hw_1 solution - Homework#1 Solution For Sand Given m1:=...

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