{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

CH16-HW02-FALL2010

# CH16-HW02-FALL2010 - 1 CH16-HW02-FALL2010 Rachel Pereira...

This preview shows pages 1–2. Sign up to view the full content.

12/14/11 CH16-HW02-FALL2010 1/3 www.webassign.net/web/Student/Assignment-Responses/view_key?dep=3173268 Current Score : 17 / 21 Due : Sunday, September 25 2011 11:59 PM EDT 1. 10/10 points | Previous Answers MI3 16.4.X.033 Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x -axis. The ring on the left carries a uniformly distributed charge of + 38 nC, and the ring on the right carries a uniformly distributed charge of - 38 nC. What is the electric field due to the right ring at a location midway between the two rings? = < 24471.53 24500 , 0 0 , 0 0 > N/C What is the electric field due to the left ring at a location midway between the two rings? = < 24471.53 24500 , 0 0 , 0 0 > N/C What is the net electric field at at a location midway between the two rings? = < 48943.06 48900 , 0 0 , 0 0 > N/C If a charge of -9 nC were placed midway between the rings, what would be the force exerted on this charge by the rings? = < -4.40e-4 -0.00044 , 0 0 , 0 0 > N Read the eBook Section 16.4 2. 3/3 points | Previous Answers MI3 16.5.X.005 For a disk of radius R = 15 cm and Q = 5 10 -6 C, calculate the magnitude of the electric field 2

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern