{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW_4_solution

# HW_4_solution - PGE 312 Physical and Chemical Behavior of...

This preview shows pages 1–3. Sign up to view the full content.

PGE 312 Physical and Chemical Behavior of Petroleum Fluids I Homework 4, Fall 2007 Problem 12-6 Component Mass(lb) Pv(psia) MW (lb/ib-mole) 1 2,2-dimethylbutene 3 9.2 88.177 2 2,2,4-trimethylpentane 2 1.7 114.231 n=Mass/MW n 1 =3/88.177=0.034 n 2 =2/114.231=0.0175 N i i n n Z 1 1 Z 1 =0.034/0.0515=0.66 Z 2 =0.0175/0.0515=0.34 1 ) 1 ( 1 1 1 N i vi g j N i i p p n Z x 1 ) 1 5 7 . 1 ( 1 34 . 0 ) 1 5 2 . 9 ( 1 66 . 0 g g n n Using the trial and error procedure g n =0.598, l n =1- g n =0.402 439 . 0 ) 1 5 2 . 9 ( 598 . 0 1 66 . 0 1 x , 561 . 0 1 1 2 x x p p x y vi i i 81 . 0 5 2 . 9 439 . 0 1 1 p p x y vi , 19 . 0 5 7 . 1 561 . 0 2 2 p p x y vi lb lb lb n M lb lb lb n M n n n n n n n n l l g g g l l g g 05 . 1 5 021 . 0 5 55 . 1 5 031 . 0 5 021 . 0 0515 . 0 402 . 0 ) 1 ( 031 . 0 0515 . 0 598 . 0

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Problem 12-8 P (psia) = 5 At bubble point conditions, ∑z i P vi = 5. Therefore, iterating for bubble pt. temperature (T B ) using the values of P vi from Fig 2-8 1st iteration 2nd iteration 3rd iteration Component z T B 90 T B 85 T B 86 1 0.67 P V1 7.5 P V1 6.7 P V1 6.9 2 0.33 P V2 1.7 P V2 1.4 P V2 1.25 1 ∑z i P vi = 5.59 ∑z i P vi = 4.95
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 8

HW_4_solution - PGE 312 Physical and Chemical Behavior of...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online