HW_4_solution - PGE 312 Physical and Chemical Behavior of...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
PGE 312 Physical and Chemical Behavior of Petroleum Fluids I Homework 4, Fall 2007 Problem 12-6 Component Mass(lb) Pv(psia) MW (lb/ib-mole) 1 2,2-dimethylbutene 3 9.2 88.177 2 2,2,4-trimethylpentane 2 1.7 114.231 n=Mass/MW n 1 =3/88.177=0.034 n 2 =2/114.231=0.0175 N i i n n Z 1 1 Z 1 =0.034/0.0515=0.66 Z 2 =0.0175/0.0515=0.34 1 ) 1 ( 1 1 1 N i vi g j N i i p p n Z x 1 ) 1 5 7 . 1 ( 1 34 . 0 ) 1 5 2 . 9 ( 1 66 . 0 g g n n Using the trial and error procedure g n =0.598, l n =1- g n =0.402 439 . 0 ) 1 5 2 . 9 ( 598 . 0 1 66 . 0 1 x , 561 . 0 1 1 2 x x p p x y vi i i 81 . 0 5 2 . 9 439 . 0 1 1 p p x y vi , 19 . 0 5 7 . 1 561 . 0 2 2 p p x y vi lb n M n M n n n n n n n n l l g g g l l g g 05 . 1 5 021 . 0 5 55 . 1 5 031 . 0 5 021 . 0 0515 . 0 402 . 0 ) 1 ( 031 . 0 0515 . 0 598 . 0
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Problem 12-8 P (psia) = 5 At bubble point conditions, ∑z i P vi = 5. Therefore, iterating for bubble pt. temperature (T B ) using the values of P vi from Fig 2-8 1st iteration 2nd iteration 3rd iteration Component z T B 90 T B 85 T B 86 1 0.67 P V1 7.5 P V1 6.7 P V1 6.9 2 0.33 P V2 1.7 P V2 1.4 P V2 1.25 1 ∑z i P vi = 5.59 ∑z i P vi = 4.95 ∑z i P vi = 5.04
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 8

HW_4_solution - PGE 312 Physical and Chemical Behavior of...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online