12 - 12-8 Iteration1 Iteration 2 Iteration 3 Component Z TB...

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Unformatted text preview: 12-8 Iteration1 Iteration 2 Iteration 3 Component Z TB 90 TB 85 TB 86 1 0.67 PV1 7.5 PV1 6.7 PV1 6.9 2 0.33 PV2 1.7 PV2 1.4 PV2 1.25 Σ 1 ΣziPvi = 5.59 ΣziPvi = 4.95 ΣziPvi = 5.04 Therefore, the bubblepoint temperature = 86 oF Iteration1 Iteration 2 Iteration 3 Component Z TD 150 TD 110 TD 115 1 0.67 PV1 23 PV1 11 PV1 12 2 0.33 PV2 5 PV2 2.1 PV2 2.35 Σ 1 1/(ΣziPvi) = 10.51 1/(ΣziPvi) = 4.59 1/(ΣziPvi) = 5.10 Therefore, the dewpoint temperature = 115 oF 12-17 A) Where P= 250 250 170 170 200 200 Zi Ki ZiKi Ki ZiKi Ki ZiKi Propane 0.4654 1.4000 0.6515 1.9500 0.9075 1.7050 0.7935 n-Butane 0.2118 0.5500 0.1165 0.7500 0.1589 0.6450 0.1366 n-Pentane 0.2275 0.2400 0.0546 0.3000 0.0683 0.2700 0.0614 n-Hexane 0.0953 0.0930 0.0089 0.1200 0.0114 0.1070 0.0102 0.8315 1.1460 1.0017 200 therefore, the bubblepoint pressure = psia C.) Where p= 100 100 50 50 73 Zi Ki Zi/Ki Ki Zi/Ki Ki Zi/Ki Propane 0.465 3.1000 0.1501 5.9000 0.0789 4.3000 0.1082 n-Butane 0.212 1.1700 0.1811 2.1700 0.0976 1.5500 0.1367 n-Pentane 0.228 0.4700 0.4841 0.8800 0.2586 0.6300 0.3612 n-Hexane 0.095 0.1800 0.5292 0.3300 0.2886 0.2400 0.3969 Σ 1.3445 1.0030 0.7237 therefore, the bubblepoint pressure = 73 psia E and F) mi lb Mi lb/lbmol Zi ni/n Ki 44.10 Ni-mi/Mi lbmol 0.567 Propane 25 0.465 2.22 N-Butane 15 58.12 0.258 0.212 0.83 n-Pentane 20 72.15 0.277 0.228 0.33 N-Hexane 10 86.18 0.116 0.095 0.13 1.218 1.000 Sum For the following nL bar values Yi=zi/[1-(nLbar*(P/(Pvi-1)))] yi yi yi Xi ML lb/lbmol Mg lb/lbmol 0.5 0.6 .589 0.6417 0.6943 0.6881 0.3100 13.67 30.34 0.1922 0.1887 0.1890 0.2278 13.24 10.99 0.1129 0.1026 0.1036 0.3140 22.66 7.48 0.0219 0.0190 0.0193 0.1483 12.78 1.66 0.9687 1.0045 1.0000 1.000 62.34 50.47 ...
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This note was uploaded on 12/14/2011 for the course PGE 312 taught by Professor Peters during the Spring '08 term at University of Texas at Austin.

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12 - 12-8 Iteration1 Iteration 2 Iteration 3 Component Z TB...

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