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Unformatted text preview: Problem 121 , = = ℎ .
+
+ = (2) = 1 (3) ℎ ℎ
Simultaneously solving (2) and (3) −
− =
= 1− (4)
−
− = (5) To calculate the gas composition, we need Dalton’s law of partial pressure
=
Also, from Raoult’s law, = (6) (7) Eliminating Pj from equations (6) and (7), we get
=
Thus = = (1) (9) = = Problem 1214
= 1.224 > 1 = 1.1095 > 1
Since both these equations are satisfied, two phases exist.
nLbar = 0.65 nLbar = 0.5 nLbar = 0.53 Xi=Yi/Ki zi Ki Yi Yi Yi Propane 0.65 1.44 0.811 0.767 0.776 0.539 nButane 0.3 0.54 0.193 0.210 0.207 0.383 nPentane 0.05 0.23 0.016 0.019 0.018 0.078 1.020 0.995 1.000 Total The composition is given by:
X1 = 0.539
X2 = 0.383
X3 = 0.078
and
Y1 = 0.776
Y2 = 0.207
Y3 = 0.018 Therefore the dewpoint pressure is 73 psia The composition of liquid is yi = zi/(1+nLbar(1/Ki – 1)) Special Problem ...
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This note was uploaded on 12/14/2011 for the course PGE 312 taught by Professor Peters during the Spring '08 term at University of Texas.
 Spring '08
 Peters

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