PGE312_Spring2009_solution_HW4

PGE312_Spring2009_solution_HW4 - Problem 12-1 , = = ℎ . +...

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Unformatted text preview: Problem 12-1 , = = ℎ . + + = (2) = 1 (3) ℎ ℎ Simultaneously solving (2) and (3) − − = = 1− (4) − − = (5) To calculate the gas composition, we need Dalton’s law of partial pressure = Also, from Raoult’s law, = (6) (7) Eliminating Pj from equations (6) and (7), we get = Thus = = (1) (9) = = Problem 12-14 = 1.224 > 1 = 1.1095 > 1 Since both these equations are satisfied, two phases exist. nL-bar = 0.65 nL-bar = 0.5 nL-bar = 0.53 Xi=Yi/Ki zi Ki Yi Yi Yi Propane 0.65 1.44 0.811 0.767 0.776 0.539 n-Butane 0.3 0.54 0.193 0.210 0.207 0.383 n-Pentane 0.05 0.23 0.016 0.019 0.018 0.078 1.020 0.995 1.000 Total The composition is given by: X1 = 0.539 X2 = 0.383 X3 = 0.078 and Y1 = 0.776 Y2 = 0.207 Y3 = 0.018 Therefore the dewpoint pressure is 73 psia The composition of liquid is yi = zi/(1+nL-bar(1/Ki – 1)) Special Problem ...
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PGE312_Spring2009_solution_HW4 - Problem 12-1 , = = ℎ . +...

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