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Unformatted text preview: Hint: To find c, we need to solve equation that will result in the following 40 = 9 . 8 ∙ 68 . 1 ࠵ ( 1 − ࠵ ! ! !" . ! !" ) or in other words, we need to solve ࠵ ࠵ = 9 . 8 ∙ 68 . 1 ࠵ 1 − ࠵ ! ! !" . ! !" − 40 = Problem 2 For the function ࠵ ࠵ = 3 ࠵ + sin ࠵ − ࠵ ! , find one root in the interval [0,1] (i.e. ࠵ ! = , ࠵ ! = 1 using the bisection method. Terminate your calculations when you are certain that the error between your approximation and actual solution to the equation ࠵ ࠵ = is less that 0.05. Explain why and how you decided to stop further iterations of bisecting the interval. Problem 3 Comment on the pros and cons of the bisection and false position methods (the false position method was discussed at the end of the lecture on September 1 st , 2011)....
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 Fall '08
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