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Cramer’s Method Example
Given:
12
52
1
3
xx
−=
−
−+ =
Put into the form
Ax = b
1
2
1
11
3
x
x
−−
⎡⎤
⎡⎤⎡
⎤
=
⎢⎥
⎢⎥⎢
⎥
−
⎣⎦⎣
⎦
⎣⎦
Which is in the form
11
12
1
1
21
22
2
2
aa
x
b
x
b
⎡
⎤
⎡
⎤
=
⎢
⎥
⎢
⎥
⎣
⎦
⎣
⎦
Allows us to determine the values of the
x
vector with the following equations:
2
22
2
1
11
12
21
22
det
det
31
5
3
det
det
ba
x
⎡⎤⎡⎤
⎢⎥⎢⎥
==
=
−
⎡
⎤
⎢
⎥
−
11
1
21
2
2
11
12
21
22
51
det
det
13
14
3
det
det
ab
x
−
−
=
−
⎡
⎤
⎢
⎥
−
which is easily checked with
()
5
14
33
5
14
1
3
−
−+
=
For solving sets of linear equations, the Cramer’s Method is
•
PLUS – general and easy to program,
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This note was uploaded on 12/14/2011 for the course ME 218 taught by Professor Unknown during the Fall '08 term at University of Texas at Austin.
 Fall '08
 Unknown

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